Answer:
0.005+0.0006+0.00002=0.00562
Step-by-step explanation:
I think its how you do it
The maximum height of the projectile is the maximum point that can be gotten from the projectile equation
The projectile reaches the maximum height after 5 seconds
The function is given as:

Differentiate the function with respect to t

Set to 0

So, we have:

Collect like terms


Solve for t


Hence, the projectile reaches the maximum after 5 seconds
Read more about maximum values at:
brainly.com/question/6636648
Not sure i remember this but i think radius is like half of the diameter. it’s a line from the center, to a side of the circle. in this situation, line RO would be representing the radius.
answer: D, line RO
hope this helps :)