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3 years ago

HELP ME PLEASE IXL !!

Mathematics

1 answer:

Inga [223]3 years ago

4 0

Answer:

3.6

Step-by-step explanation:

hey, how this helps and is right haha

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A bag contains 7 pieces of paper numbered 1 to 7. P(2)=. Is this an experimental or theoretical probability and why?

Lera25 [3.4K]

Answer:

theoretical probability

Step-by-step explanation:

This is theoretical probability. The 7 pieces of paper each bear one number from {1, 2, ... , 6, 7}. There is only one piece of paper marked 7. So the probability of drawing a 2 is 1/7.

4 0

3 years ago

F(x) = x + 2<br> g(x) = x - 4<br> (f9)(x) =

san4es73 [151]

Answer:

(fºg)(x) = x -2

Step-by-step explanation:

f(x) = x + 2

g(x) = x - 4

(fºg)(x) = ( x - 4) + 2

(fºg)(x) = x -2

3 0

3 years ago

Prove A-(BnC) = (A-B)U(A-C), explain with an example

NikAS [45]

Answer:

Prove set equality by showing that for any element $x$ , $x \in (A \backslash (B \cap C))$ if and only if $x \in ((A \backslash B) \cup (A \backslash C))$ .

Example:

$A = \lbrace 0,\, 1,\, 2,\, 3 \rbrace$ .

$B = \lbrace0,\, 1 \rbrace$ .

$C = \lbrace0,\, 2 \rbrace$ .

$\begin{aligned} & A \backslash (B \cap C) \\ =\; & \lbrace 0,\, 1,\, 2,\, 3 \rbrace \backslash \lbrace 0 \rbrace \\ =\; & \lbrace 1,\, 2,\, 3 \rbrace \end{aligned}$ .

$\begin{aligned}& (A \backslash B) \cup (A \backslash C) \\ =\; & \lbrace 2,\, 3\rbrace \cup \lbrace 1,\, 3 \rbrace \\ =\; & \lbrace 1,\, 2,\, 3 \rbrace\end{aligned}$ .

Step-by-step explanation:

Proof for $[x \in (A \backslash (B \cap C))] \implies [x \in ((A \backslash B) \cup (A \backslash C))]$ for any element $x$ :

Assume that $x \in (A \backslash (B \cap C))$ . Thus, $x \in A$ and $x \not \in (B \cap C)$ .

Since $x \not \in (B \cap C)$ , either $x \not \in B$ or $x \not \in C$ (or both.)

If $x \not \in B$ , then combined with $x \in A$ , $x \in (A \backslash B)$ .
Similarly, if $x \not \in C$ , then combined with $x \in A$ , $x \in (A \backslash C)$ .

Thus, either $x \in (A \backslash B)$ or $x \in (A \backslash C)$ (or both.)

Therefore, $x \in ((A \backslash B) \cup (A \backslash C))$ as required.

Proof for $[x \in ((A \backslash B) \cup (A \backslash C))] \implies [x \in (A \backslash (B \cap C))]$ :

Assume that $x \in ((A \backslash B) \cup (A \backslash C))$ . Thus, either $x \in (A \backslash B)$ or $x \in (A \backslash C)$ (or both.)

If $x \in (A \backslash B)$ , then $x \in A$ and $x \not \in B$ . Notice that $(x \not \in B) \implies (x \not \in (B \cap C))$ since the contrapositive of that statement, $(x \in (B \cap C)) \implies (x \in B)$ , is true. Therefore, $x \not \in (B \cap C)$ and thus $x \in A \backslash (B \cap C)$ .
Otherwise, if $x \in A \backslash C$ , then $x \in A$ and $x \not \in C$ . Similarly, $x \not \in C \!$ implies $x \not \in (B \cap C)$ . Therefore, $x \in A \backslash (B \cap C)$ .

Either way, $x \in A \backslash (B \cap C)$ .

Therefore, $x \in ((A \backslash B) \cup (A \backslash C))$ implies $x \in A \backslash (B \cap C)$ , as required.

8 0

3 years ago

Describe the difference between vertical angles and linear pairs of angles

Anvisha [2.4K]

The difference between vertical angles and linear pairs of angles is that linear pairs of angles has two adjacent angles whose noncommon sides form opposite sides and vertical angles have two adjacent angles that have common sides that and they have a common vertex.

3 0

3 years ago

Read 2 more answers

PLZ HELP!!!! solve for x

kumpel [21]

Answer:

64 degrees

Step-by-step explanation:

Combining the 90 degrees, x degrees, and 26 degrees creates a flat angle or 180 degrees

so first, combine 90 and 26 degrees

90+26= 116

then subtract 116 from 180

180-116= 64 degrees

5 0

3 years ago