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amid [387]
3 years ago
12

the claim that 20% of americans know their credit score is tested. suppose that the sample evidence causes us to fail to reject

the null hypothesis claim that 20% of americans know their credit score. state the final conclusion in simple non technical terms
Mathematics
1 answer:
kipiarov [429]3 years ago
5 0

Answer:

Conclusion : People ≠ 20% don't know about their credit score.

Step-by-step explanation:

Hypothesis is testing a statement for its statistical significance.

Null Hypothesis (H0)  implies 'no difference from tested value', Alternate hypothesis (H1)  implies 'significant difference from tested value'

Let % of people knowing their credit score = CS

H0 : CS = 20

H1 : CS  ≠  20

If the null hypothesis is rejected, it implies that we reject the claim that CS i.e '% of americans knowing their credit score = 20%'. So, the alternate hypothesis is accepted, i.e we conclude that '% americans knowing their credit score ≠ 20%'.

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swat32

Answer:

The solution is:

Part A. \sqrt{5}^{\frac{7k}{3}}) which is sqrt(5)^7k/3[/tex]

Part B. k = 18/7

Step-by-step explanation:

Part A.

To solve this part, we're going two use THREE important properties of exponents:

1. (x^{n})^{m} = x^{nm}

2. \frac{x^{n}}{x^{m}} = x^{n-m}

3. \sqrt[n]{x^{m}} = x^{\frac{m}{n} }

Let's work the numerator using the properties 1, 2 and 3:

(\sqrt{5}^{3} )^{\frac{k}{9} } }  = (\sqrt{5}^{3\frac{k}{9}}) = (\sqrt{5}^{\frac{k}{3}})

Let's work the denominator using the properties 1, 2 and 3:

(\sqrt{5}^{6} )^{-\frac{k}{3} } }  = (\sqrt{5}^{6\frac{k}{3}}) = (\sqrt{5}^(2k))

Now dividing the numerator by the denominator:

\sqrt{5}^{\frac{k}{3}-(-2k)})=\sqrt{5}^{\frac{7k}{3}})

Part B

if 5^{\frac{3}{2} } 5^{\frac{3}{2}} = \sqrt{5}^{\frac{7k}{3}})

Then:

5^{3} = 5^{\frac{7k}{6}})

So \frac{7k}{6}} = 3

Solving for k, we have:

k = 18/7

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3 years ago
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Step-by-step explanation:

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Formula of area of square
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Area of square = Length x Length
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Answer:

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