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Alenkinab [10]
3 years ago
15

Shelly biked 21 miles in 4 hours. How long will it take Shelly to bike 63 miles? HELP ASAP!! PLEASE!!!!

Mathematics
2 answers:
oee [108]3 years ago
8 0

Answer:

12 hours

Step-by-step explanation:

21 miles - 4 hours

63 miles - x hours

x = 63 x 4/21 = 12 hours

vaieri [72.5K]3 years ago
3 0

12 hours-

21/4=5.25

5.25x12=63

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Which facts could be applied to simplify this expression? Select three options.
kumpel [21]

Answer:

A, B, and D

Step-by-step explanation:

To subtract like terms, you're supposed to subtract the coefficients, so <u><em>Option 1 is correct</em></u>. The statement like terms are terms that contain the same variable, raised to the same power, is true, so <u><em>Option 2 is correct</em></u>. The simplified expression is -4 - 3y + 3z, so Option 3 is wrong and <u><em>Option 4 is correct</em></u>. Option 5, -(-x) = -x is wrong, so Option 5 is not correct. Therefore, the answers are Options 1, 2, and 4 (or A, B, and D).

Hope this helps! I got it right on Edgen.

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3 years ago
20 adults and 15 children are going to attend a musical evening. The organizers have arranged the tables in such a way that ther
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Step-by-step explanation:

20 + 15 = 35 . Now you need to list the factor of 35:    1, 5, 7, 35 pickt the smallest factor.

3 0
3 years ago
A university researcher wants to estimate the mean number of novels that seniors read during their time in college. An exit surv
lys-0071 [83]

Answer:

Population mean = 7 ± 2.306 × \frac{2.29}{\sqrt{9} }

Step-by-step explanation:

Given - A university researcher wants to estimate the mean number

            of  novels that seniors read during their time in college. An exit

            survey was conducted with a random sample of 9 seniors. The

            sample mean was 7 novels with standard deviation 2.29 novels.

To find - Assuming that all conditions for conducting inference have

              been met, which of the following is a 94.645% confidence

              interval for the population mean number of novels read by

              all seniors?

Proof -

Given that,

Mean ,x⁻ = 7

Standard deviation, s = 2.29

Size, n = 9

Now,

Degrees of freedom = df

                                = n - 1

                                = 9 - 1

                                = 8

⇒Degrees of freedom = 8

Now,

At 94.645% confidence level

α = 1 - 94.645%

   =1 - 0.94645

  =0.05355 ≈ 0.05

⇒α = 0.5

Now,

\frac{\alpha}{2} = \frac{0.05}{2}

  = 0.025

Then,

t_{\frac{\alpha}{2}, df }  = 2.306

∴ we get

Population mean = x⁻ ± t_{\frac{\alpha}{2}, df } ×\frac{s}{\sqrt{n} }

                           = 7 ± 2.306 × \frac{2.29}{\sqrt{9} }

⇒Population mean = 7 ± 2.306 × \frac{2.29}{\sqrt{9} }

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