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Gnoma [55]
3 years ago
13

Please help find mDF!!

Mathematics
1 answer:
Natalka [10]3 years ago
4 0

9514 1404 393

Answer:

  72°

Step-by-step explanation:

The external angle E is half the difference of subtended arcs CG and DF.

  E = (CG -DF)/2

  2E = CG -DF . . . . . . multiply by 2

  DF = CG -2E = 160° -2(44°) . . . . . add DF-2E to both sides; substitute values

  arc DF = 72°

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If a loan option had been available for your food truck for the $50,000 at 4% interest for 6 years instead of 4 would you have t
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Answer:

It depends.

Step-by-step explanation:

For 6 years:

50000*(1.04)^6=\$63266

On average, you would have to be profiting:

\frac{63266}{6}=\$10544 per year

For 4 years:

50000*(1.04)^4=\$58492

On average, you would have to be profiting:

\frac{58492}{4} = \$14623 per year.

It would be better to have the longer term option - although you will be paying off more in total, you would be paying off a smaller portion of your earnings.

However, you may want to pay off the loan faster as you would no longer have to worry about it, and it would be cheaper to pay off over the shorter period.

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The diagram below shows two
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Answer:

4 cm

Step-by-step explanation:

\frac{8}{ST}  = \frac{4}{2} \\\\ST = 8*2 / 4\\ST = 4

6 0
3 years ago
The boiling pint of jet fuel is 329 Fahrenheit! Rounded to the nearest degree, what is the temperature in sergers Celsius? Use t
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165 degrees Celsius

Step-by-step explanation:

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3 years ago
. (0.5 point) We simulate the operations of a call center that opens from 8am to 6pm for 20 days. The daily average call waiting
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Answer:

The 95% t-confidence interval for the difference in mean is approximately (-2.61, 1.16), therefore, there is not enough statistical evidence to show that there is a change in waiting time, therefore;

The change in the call waiting time is not statistically significant

Step-by-step explanation:

The given call waiting times are;

24.16, 20.17, 14.60, 19.79, 20.02, 14.60, 21.84, 21.45, 16.23, 19.60, 17.64, 16.53, 17.93, 22.81, 18.05, 16.36, 15.16, 19.24, 18.84, 20.77

19.81, 18.39, 24.34, 22.63, 20.20, 23.35, 16.21, 21.73, 17.18, 18.98, 19.35, 18.41, 20.57, 13.00, 17.25, 21.32, 23.29, 22.09, 12.88, 19.27

From the data we have;

The mean waiting time before the downsize, \overline x_1 = 18.7895

The mean waiting time before the downsize, s₁ = 2.705152

The sample size for the before the downsize, n₁ = 20

The mean waiting time after the downsize, \overline x_2 = 19.5125

The mean waiting time after the downsize, s₂ = 3.155945

The sample size for the after the downsize, n₂ = 20

The degrees of freedom, df = n₁ + n₂ - 2 = 20 + 20  - 2 = 38

df = 38

At 95% significance level, using a graphing calculator, we have; t_{\alpha /2} = ±2.026192

The t-confidence interval is given as follows;

\left (\bar{x}_{1}- \bar{x}_{2}  \right )\pm t_{\alpha /2}\sqrt{\dfrac{s_{1}^{2}}{n_{1}}+\dfrac{s_{2}^{2}}{n_{2}}}

Therefore;

\left (18.7895- 19.5152 \right )\pm 2.026192 \times \sqrt{\dfrac{2.705152^{2}}{20}+\dfrac{3.155945^2}{20}}

(18.7895 - 19.5125) - 2.026192*(2.705152²/20 + 3.155945²/20)^(0.5)

The 95% CI = -2.6063 < μ₂ - μ₁ < 1.16025996668

By approximation, we have;

The 95% CI = -2.61 < μ₂ - μ₁ < 1.16

Given that the 95% confidence interval ranges from a positive to a negative value, we are 95% sure that the confidence interval includes '0', therefore, there is sufficient evidence that there is no difference between the two means, and the change in call waiting time is not statistically significant.

6 0
3 years ago
The radius r(t) of the base of a cone is increasing at a rate of 10 meters per second. The height h(t) of the cone is fixed at 6
IceJOKER [234]

Answer:

dV/dt = 40π

Step-by-step explanation:

We are told that The radius r(t) of the base of a cone is increasing at a rate of 10 meters per second. Thus;

dr/dt = 10 m

Height: h = 6 m

Volume of cone is given by the formula;

V = ⅓πr²h

dV/dr = ⅔πrh

We want to find the rate at which the volume is changing at radius of 1m.

Thus;

dV/dt = (dV/dr) × (dr/dt)

dV/dt = ⅔π(1 × 6) × (10)

dV/dt = 40π

8 0
3 years ago
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