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Maurinko [17]
3 years ago
10

One year, a group of doctors held a fundraiser and sent $35,885 to a clinic in need of support. Each year after that, the doctor

s sent another $2500
After how many years will the total amount sent by the doctors first exceed $250,000?
Mathematics
1 answer:
Doss [256]3 years ago
3 0

Answer:

86 years after the $35,885 donation is made

Step-by-step explanation:

Let n be the total number of years.

Each year they sent $2500, so in n year they send 2500n dollars.

They sent $35,885 to start with, so after n years, they will have sent a total of

2500n + 35,885

We need to find the value of n for which 2500n + 35,885 exceeds $250,000.

2500n + 35,885 > 250,000

2500n > 214,115

n > 214,115/2500

n > 85.6

The first year after 85.6 years have passed is year 86.

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Answer:

B. 1 + ln 2 - ln x

General Formulas and Concepts:

<u>Algebra II</u>

  • Natural logarithms ln and Euler's number e
  • Logarithmic Property [Multiplying]:                                                                     \displaystyle log(ab) = log(a) + log(b)
  • Logarithmic Property [Dividing]:                                                                         \displaystyle log(\frac{a}{b}) = log(a) - log(b)<u> </u>

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

<em />\displaystyle ln(\frac{2e}{x})<em />

<em />

<u>Step 2: Simplify</u>

  1. Expand [Logarithmic Property - Dividing]:                                                      \displaystyle ln(\frac{2e}{x}) = ln(2e) - ln(x)
  2. Expand [Logarithmic Property - Multiplying]:                                                  \displaystyle ln(\frac{2e}{x}) = ln(2) + ln(e) - ln(x)
  3. Simplify:                                                                                                             \displaystyle ln(\frac{2e}{x}) = ln(2) + 1 - ln(x)
  4. Rewrite:                                                                                                             \displaystyle ln(\frac{2e}{x}) = 1 + ln(2) - ln(x)
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3 years ago
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7 0
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8 0
4 years ago
Read 2 more answers
What the explicit formula of 3 5 7 9
SIZIF [17.4K]

Answer:

a_{n}=3+2(n-1)

Step-by-step explanation:

Given:

The given sequence is 3, 5, 7, 9

The difference between the second and first term is 5 - 3 = 2

The difference between the third and second term is 7 - 5 = 2

The difference between the fourth and third term is 9 - 7 = 2

So, there is a common difference of 2. Thus a sequence which has the same difference is known as an arithmetic sequence.

The explicit formula to determine the n^{th} term of an arithmetic sequence is given as:

a_n=a_1+(n-1)d

Where, a_1\rightarrow 1^{st}\ term, d\rightarrow \textrm{common difference}

Plug in 3 for a_1 and 2 for d. This gives,

a_{n}=3+(n-1)\times 2

Therefore, the explicit formula to represent the given sequence is:

a_{n}=3+2(n-1)

7 0
4 years ago
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