Answer:
There is one extraneous solution at 
The only solution is 
Step-by-step explanation:
Given:
The equation to solve is given as:

In order to solve, we will first isolate the radical part.
<em>Adding -5 on both the sides, we get:</em>

<em>Now, squaring both the sides, we get:</em>

Now, let us check whether the calculated values satisfy the equations or not.
Plug in 4 and 7 for 'x' and check the value of the equation.
At
,

But, 6 is not equal to 4 and hence 4 is not a solution to the given equation. It is an extraneous solution for the given equation.
Now, at 

Therefore,
is a solution to the equation.
Hence, there is one extraneous solution at 
The only solution is 