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notsponge [240]
3 years ago
14

Does this set of ordered pairs represent a function? Why or why not? {(–1, 5), (0, –3), (2, 7), (4, 0), (7, 5)} A. No, because t

wo of the y-values are the same. B. No, because one x-value corresponds to two different y-values. C. Yes, because every x-value corresponds to exactly one y-value. D. Yes, because there are two x-values that are the same.
Mathematics
1 answer:
iVinArrow [24]3 years ago
4 0

9514 1404 393

Answer:

  C. Yes, because every x-value corresponds to exactly one y-value.

Step-by-step explanation:

The list of x-values is {-1, 0, 2, 4, 7}. We note that no two are the same, so this is a functional relation.

The set of ordered pairs is a function because each x-value corresponds to exactly one y-value.

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Would it be factoring a polynomial,
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Factoring a polynomial
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(3x-5)/(x-5)&gt;=0 <br> How do I get the answers for this problem?
Diano4ka-milaya [45]
\frac{3x-5}{x-5} > 0 

First, note that x is undefined at 5. / x ≠ 5
Second, replace the inequality sign with an equal sign so that we can solve it like a normal equation. / Your problem should look like: \frac{3x-5}{x-5} = 0
Third, multiply both sides by x - 5. / Your problem should look like: 3x - 5 = 0
Forth, add 5 to both sides. / Your problem should look like: 3x = 5
Fifth, divide both sides by 3. / Your problem should look like: x = \frac{5}{3}
Sixth, from the values of x above, we have these 3 intervals to test: 
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Seventh, pick a test point for each interval. 

1. For the interval x < \frac{5}{3} :
Let's pick x - 0. Then, \frac{3x0-5}{0-5} > 0
After simplifying, we get 1 > 0 which is true.
Keep this interval.

2. For the interval \frac{5}{3} < x < 5:
Let's pick x = 2. Then, \frac{3x2-5}{2-5} > 0
After simplifying, we get -0.3333 > 0, which is false.
Drop this interval.

3. For the interval x > 5:
Let's pick x = 6. Then, \frac{3x6-5}{6-5} > 0
After simplifying, we get 13 > 0, which is ture.
Keep this interval.
Eighth, therefore, x < \frac{5}{3} and x > 5

Answer: x < \frac{5}{3} and x > 5

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4 years ago
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