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3 years ago

Please help me I will give u a brainliest only if correct

Mathematics

2 answers:

Anna007 [38]3 years ago

8 0

The answer is C 7 units 2

Luden [163]3 years ago

4 0

I got 6 units^2. So the answer is the second choice. ab/2 = 3*4/2 = 6.

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Simplify. Write the expression using only positive exponents. 3d^−4⋅4d^4 PPPLLLLEEEASSSEEEEE

bixtya [17]

Answer:

d=0

Step-by-step explanation:

Because multiplication is commutative, we can rearrange the expression however we want. So, let's put the constant expressions together, and the variable expressions together:

(3 x 4) x (d^-4 x d^4)

The first term is easy enough: (3 x 4) = 12

For the second term, when exponent terms have the same "base" (in this case, d), the exponents can be added together. So, the second term yields d^(-4 + 4) = d^0. Any number raised to the zero power equals 1, EXCEPT for the sole number of zero. 0^0 is undefined, but any other number raised to the zero power equals 1.

So, if d equals any number other than zero, the expression becomes

(12) x (1) = 12

The best way to express the answer would be that the expression equals 12 except that it is undefined if d=0

5 0

3 years ago

HELP DUE IN 10 MINS!

Scilla [17]

Answer:

$\checkmark \text{B. The area of the circle is } 729\pi,\\\checkmark \text{D. The arc length of the sector is } 12\pi$

Step-by-step explanation:

Area of a circle with radius $r$ : $r^2\pi$

Circumference of a sector with radius $r$ : $2r\pi$

Area of sector with angle $\theta$ : $r^2\pi\cdot \frac{\theta}{360}$ .

Arc length of sector with angle $\theta$ : $2r\pi\cdot \frac{\theta}{360}$

Using these equations, we get the following information:

Area of circle: $27^2\pi=729\pi$

Circumference of a circle: $2\cdot 27\cdot \pi=54\pi$

Area of sector: $27^2\pi\cdot \frac{80}{360}=162\pi$

Arc length of sector: $2\cdot 27\cdot \pi \cdot \frac{80}{360}=12\pi$

3 0

3 years ago

Which expression is equivalent to -18a^-2b^5/-12a^-4b^-6

crimeas [40]

Answer:

c. 3a^2b^11/2

Step-by-step explanation:

The applicable rule of exponents is ...

(a^b)/(a^c) = a^(b-c)

$\dfrac{-18a^{-2}b^5}{-12a^{-4}b^{-6}}=\dfrac{-18}{-12}a^{-2-(-4)}b^{5-(-6)}=\boxed{\dfrac{3a^2b^{11}}{2}}$

3 0

2 years ago

Find the slope of the line using the ordered pairs (-1, -3/4) and (4, -3)

wel

Answer:

- 2.25/3

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Solve the system of linear equations by substitution

Bond [772]

Answer:

(-4, 5)

Step-by-step explanation (work shown in attached picture):

1) Since x is already isolated in the first equation, substitute that value for x into the other equation to find y. So, substitute 16-4y for the x in 3x + 4y = 8, then solve for y. This gives us y = 5.

2) Now, substitute that given value for y back into any one of the equations to find x. I chose to do it in the first equation. Substitute 5 for the y in x = 16-4y, then solve for x this time. This gives us x = -4.

Since x = -4 and y = 5, the solution is (-4, 5).

5 0

2 years ago