Answer:
2.866 x 10^8 J
Explanation:
Thermal conductivity, K = 0.040 W/m^2 k
Area of the wall, A = 470 m^2
Thickness, d = 17 cm = 0.17 m
difference in temperature, ΔT = 30° C
The rate of heat flow is H.
Time, t = 1 day = 1 x 24 x 60 x 60 second = 86400 second
By use of formula of heat flow


H = 2.866 x 10^8 J
The length by which the spring got stretched will be 0.08 m. The force is directly propotional to the distance by which the spring stretched.
<h3>What is spring force?</h3>
The force required to extend or compress a spring by some distance scales linearly with respect to that distance is known as the spring force. Its formula is
F = kx
The given data in the problem is;
F is the spring force =200
K is the spring constant= 2500 N/m
x is the length by which spring got stretched =?
The stretch of the spring is found as;

Hence the length by which the spring got stretched will be 0.08 m.
To learn more about the spring force refer to the link;
brainly.com/question/4291098
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Answer:
I'm not sure but I think it's 4.5 v