The frequency is exactly the rate at which the bug beats its wings.
If that "600" that you mentioned is 600 beats per second, then
THAT's the frequency . . . 600 per second. (600 Hz)
Answer:
61.22m
Explanation:
Maximum height in projectile is expressed as;
H = u²sin²θ/2g
u is the speed
g is the acceleration due to gravity
θ is the angle of projection
Substitute the given values into the formula;
H = u²sin²θ/2g
H = 40²sin²60/2g
H = 1600(0.8660)²/2(9.8)
H = 1600(0.8660)²/2(9.8)
H = 1,199.9/19.6
H = 61.22m
Hence the maximum height achieved by the ball is 61.22m
Answer:
Explanation:
Let the intensity of the noise be represented by I
Given that
40dB = 10 log 10 ( I /I•) ........ 1
I• is the lowest or threshold intensity of sound made.
I represents the intensity of the sound/ noise
The intensity of noise of 1000flies will be
β = 10 log 10 (1000I/I•)
Open up the bracket
β = 10 log 10(1000)+ 10 log 10(I/I•)
10 log 10(10^3)+10 log 10(I/I•)
3×10(10 log 10) +10 log 10(I/I•)
Recall, 10 log 10 = 1
30×1 + 10 log 10(I/I•).........2
Put equation 1 into 2
β =30+40
= 70db
Question four bulbs A,B,C and D are connected in a circuit shown in the figure below, the letters X, Y and Z represent three switches. Which switch is used to operate switch A separately?
Answer: x
Answer:
The magnitude of the force between the two parallel wires is 0.0111 N.
Explanation:
Given;
length of the two parallel wires, L = 42 m
distance between the two wires, r = 0.03 m
current in both wires, I₁, I₂ = 6.3 A
Therefore, the magnitude of the repulsive force between the two parallel wires is given by;
Therefore, the magnitude of the force between the two parallel wires is 0.0111 N.
