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3 years ago

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Which evidence supports the big band theory select 3 options

1 answer:

ruslelena [56]3 years ago

5 0

Answer:

Explanation:

There are different theories and evidence about the big bang, in this case, we're going to see three evidence.

The galaxies are moving from us, this means space is expanded, this in consequence Big Bang's explosion.

The cosmic microwave background radiation is related to the early warmth of the universe.

The observed abundance of hydrogen, helium, deuterium, lithium, these are checked from the spectra of the oldest stars.

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A 2.9-kg cart is rolling across a frictionless, horizontal track toward a 1.4-kg cart that is held initially at rest. The carts

VikaD [51]

Answer:

The question is incomplete. I will assume you intend to find the total momentum of the two carts during collision. Therefore, we can use the conservation of momentum principle to get the total momentum at a certain instant before collision.

Explanation:

The conservation of momentum principle states that the initial net momentum of two bodies before collision is equal to the final net momentum after collision.

In this case, let's denote the rolling cart as <em>'a'</em> and the stationary cart as <em>'b'</em>.

$Momentum, P = MaVa +MbVb$

$P=(2.9)(+4.7) + (1.4)(-1.9)\\P= 13.68 + (-2.66)\\P= 13.68-2.66\\P=+11.02 Kg.m/s$

Therefore, the total momentum before collision is 11.02 Kg.m/s.

6 0

3 years ago

A car traveling at 37m/s starts to decelerate steadily. It comes to a complete stop in 15 seconds. What is it’s acceleration

LuckyWell [14K]

<u>Answer</u>

The acceleration is

$a=-2.5ms^{-2}$ to the nearest tenth

<u>Explanation</u>

Since the car was travelling at $37ms^{-1}$ before it starts to decelerate, the initial velocity is

$u=37ms^{-1}$ .

The final velocity is $v=0ms^{-1}$ , because the car came to a stop.

The time taken is $t=15s$ .

Using the Newton's equation of linear motion,

$v=u +at$ , we find the acceleration by substituting the known values.

This implies that,

$0=37 +a(15)$

This gives us,

$0-37=15a$

$\Rightarrow -37=15a$

We divide both sides by 15 to get,

$a=-\frac{37}{15}ms^{-2}$

or

$a=-2.46667ms^{-2}$

6 0

3 years ago

Suppose that the coefficient of kinetic friction between Zak's feet and the floor, while wearing socks, is 0.250. Knowing this,

insens350 [35]

Answer:

The distance travel before stopping is 1.84 m

Explanation:

Given :

coefficient of kinetic friction $\mu_{k} = 0.250$

Zak's speed $v = 3 \frac{m}{s}$

Gravitational acceleration $g = 9.8$ $\frac{m}{s^{2} }$

Work done by frictional force is given by,

$W = \Delta K$

$\mu _{k} mg d = \frac{1}{2} m v^{2}$

$d = \frac{v^{2} }{2 g \mu _{k} }$

$d = \frac{9}{2 \times 9.8 \times 0.250}$

$d = 1.84$ m

Therefore, the distance travel before stopping is 1.84 m

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3 years ago

The number of protons in the nucleus is the number of blank

Tresset [83]

The number of protons in an atom identifies the Atomic Number
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3 years ago

When sugar is added to water, the sugar dissolves and the resulting liquid is clear. Have the combined sugar and water formed a

Mariana [72]

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3 years ago

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