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il63 [147K]
3 years ago
9

When running your engine, you cause debris, rocks and propeller blast to be directed towards people or other aircraft. Is this c

onsidered reckless operation of an aircraft? Explain.
Physics
1 answer:
beks73 [17]3 years ago
3 0

Answer:

Yes, it is reckless. This is because it is the responsibility of the pilot to make sure that the direction of the propeller blast is away from people or other aircraft and in a safe direction.

Explanation:

Yes, it is reckless to let the propeller blast face people and other aircraft. This is because it is the responsibility of the pilot to make sure that the direction of the propeller blast is away from people or other aircraft and in a safe direction. People and other aircraft can be injured by the debris and the rocks that are scattered by the engine of the aircraft.

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In this activity, you’ll read two articles about plastics that analyze the material from two different points of view. You’ll al
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Answer:

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Explanation:

I will read the article

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2 years ago
The hypotenuse of an isosceles right triangle is 36 units. to the nearest tenth, what is the length of one of the legs
GarryVolchara [31]
The length of one of them would be 6
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3 years ago
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2 years ago
A charged particle moves in a circular path in a uniform magnetic field.Which of the following would increase the period of the
Bond [772]

Answer:

Increasing its charge

Increasing the field strength

Explanation:

For a charged particle moving in a circular path in a uniform magnetic field, the centripetal force is provided by the magnetic force, so we can write:

qvB = m\frac{v^2}{r}

where

q is the charge

v is the velocity

B is the magnetic field

m is the mass

r is the radius of the orbit

The period of the motion is

T=\frac{2\pi r}{v}

Re-arranging for r

r=\frac{Tv}{2\pi}

And substituting into the previous equation

qvB = m \frac{Tv^3}{2\pi}

Solving for T,

T=\frac{2\pi q B}{m v^2}

So we see that the period is:

- proportional to the charge and the magnetic field

- inversely proportional to the mass and the square of the speed

So the following will increase the period of the particle's motion:

Increasing its charge

Increasing the field strength

4 0
3 years ago
Consider an oil droplet of mass m and charge q. We want to determine the charge on the droplet in a Millikan-type experiment. We
Katen [24]

Answer:

q=\frac{mg}{E_o}              

Explanation:

Given:

Charge = <em>q</em>

Electric field strength =E_o

weight of the droplet = <em>mg</em>

The charge is suspended motionless. This is because the electric force on the charge is balanced by the weight of the droplet.

electric force on charged droplet, F=qE_o

This is balanced by the weight, mg

Equating the two:

qE_o=mg\\\Rightarrow q=\frac{mg}{E_o}

4 0
3 years ago
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