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3 years ago

6

A basketball referee tosses the ball straight up for the starting tip-off. At what velocity must a basketball player leave the g

round to rise 1.25 m above the floor in an attempt to get the ball? (Assume that the player gets the ball at his maximum height.)

1 answer:

maxonik [38]3 years ago

8 0

Answer:4.95 m/s

Explanation:

Given

Ball rises to a height of 1.25 m

Let u be the velocity of player while leaving ground .

Its final velocity will be zero as he reaches a height of 1.25 m

thus

$u^2=2gh$

$u=\sqrt{2\times 9.81\times 1.25}$

$u=\sqrt{24.525}$

u=4.952 m/s

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A 3030 cmcm wrench is used to loosen a bolt with a force applied 0.30.3 mm from the bolt. It takes 6060 NN to loosen the bolt wh

kolezko [41]

Complete Question

A 30 cmcm wrench is used to loosen a bolt with a force applied 0.30m from the bolt. It takes 60 N to loosen the bolt when the force is applied perpendicular to the wrench. How much force would it take if the force was applied at a 30 degree angle from perpendicular?

Answer:

The force required is $F_{\theta } = 69.28 \ N$

Explanation:

From the question we are told that

The length of the wrench is $L = 30 cm = \frac{30}{100} = 0.3 \ m$

The distance from the bolt is $d = 0.30 m$

The force it takes to loosen the bolt is $F = 60 N$

The angle of application is $\theta = 30 ^o$

Generally the torque required to loosen the bolt is

$\tau = F * d$

$\tau = 60 * 0.3$

$\tau = 18 Nm$

Now for the bolt to be loosen at $\theta$ the torque at 90° must be the same as that at $\theta$

So the torque at $\theta$ is mathematically represented as

$\tau = F_{\theta }d cos \theta$

substituting values

$18 = F_{\theta } * 0.3 cos (30)$

$F_{\theta } = \frac{18}{0.3 cos (30)}$

$F_{\theta } = 69.28 \ N$

7 0

3 years ago

People who r good at physics pls help...

malfutka [58]

Answer:

Speed and velocity both measure an object’s rate of motion. However, speed is a scalar quantity, which means that it can be described with a numerical value. Velocity is a vector quantity, which depends on direction as well as magnitude. Read these definition for more information:

speed - the rate of distance traveled by a moving object over time

velocity - the rate of displacement of a moving object over time

Basically, an object’s speed tells you how fast it’s going. Its velocity tells you how fast it’s going in a certain direction. You use speed measurements in your daily life, but physicists depend on velocity measurements more frequently in their work.

Explanation:

5 0

3 years ago

An instrument is thrown upward with a speed of 15 m/s on the surface of planet X where the acceleration due to gravity is 2.5 m/

Katen [24]

<h2>Answer: 12 s</h2>

Explanation:

The situation described here is parabolic movement. However, as we are told <u>the instrument is thrown upward</u> from the surface, we will only use the equations related to the Y axis.

In this sense, the main movement equation in the Y axis is:

$y-y_{o}=V_{o}.t-\frac{1}{2}g.t^{2}$ (1)

Where:

$y$ is the instrument's final position

$y_{o}=0$ is the instrument's initial position

$V_{o}=15m/s$ is the instrument's initial velocity

$t$ is the time the parabolic movement lasts

$g=2.5\frac{m}{s^{2}}$ is the acceleration due to gravity at the surface of planet X.

As we know $y_{o}=0$ and $y=0$ when the object hits the ground, equation (1) is rewritten as:

$0=V_{o}.t-\frac{1}{2}g.t^{2}$ (2)

Finding $t$ :

$0=t(V_{o}-\frac{1}{2}g.t^{2})$ (3)

$t=\frac{2V_{o}}{g}$ (4)

$t=\frac{2(15m/s)}{2.5\frac{m}{s^{2}}}$ (5)

Finally:

$t=12s$

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4 years ago

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PilotLPTM [1.2K]

Answer:

it is light

Explanation:

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3 years ago

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dimaraw [331]

C because mass is how much space an object takes up

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4 years ago