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vodomira [7]
3 years ago
10

I NEED HELP PLEASE 30 points

Mathematics
2 answers:
kenny6666 [7]3 years ago
8 0
(2, 4) is the correct answer
cupoosta [38]3 years ago
6 0
(2,4)

Hope this helps
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For every 3 tickets you sell, your friend sells 4. You sell a total of 12 tickets. How many does your friend sell?
sweet [91]

the friend sold 16 tickets

4 0
3 years ago
Help me plz<br><br>does anyone know this​
Oksanka [162]

Answer:

I believe the x value is 5

Step-by-step explanation:

point A is plotted on point (5,3)

5 is x and y is 3, hope it helps

3 0
3 years ago
M=7/5, (4,-9)<br><br>Put the equation of the line in the form Ax+By=C<br>do not do file please-
NeTakaya

Answer:

y = 7/5x - 14 3/5

Step-by-step explanation:

Point-slope form:

y + 9 = 7/5(x - 4)

y + 9 = 7/5x - 28/5

y = 7/5x - 14 3/5

4 0
2 years ago
Use the substitution of x=e^{t} to transform the given Cauchy-Euler differential equation to a differential equation with consta
kherson [118]

By the chain rule,

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm dy}{\mathrm dt}\dfrac{\mathrm dt}{\mathrm dx}\implies\dfrac{\mathrm dy}{\mathrm dt}=x\dfrac{\mathrm dy}{\mathrm dx}

which follows from x=e^t\implies t=\ln x\implies\dfrac{\mathrm dt}{\mathrm dx}=\dfrac1x.

\dfrac{\mathrm dy}{\mathrm dt} is then a function of x; denote this function by f(x). Then by the product rule,

\dfrac{\mathrm d^2y}{\mathrm dx^2}=\dfrac{\mathrm d}{\mathrm dx}\left[\dfrac1x\dfrac{\mathrm dy}{\mathrm dt}\right]=-\dfrac1{x^2}\dfrac{\mathrm dy}{\mathrm dt}+\dfrac1x\dfrac{\mathrm df}{\mathrm dx}

and by the chain rule,

\dfrac{\mathrm df}{\mathrm dx}=\dfrac{\mathrm df}{\mathrm dt}\dfrac{\mathrm dt}{\mathrm dx}=\dfrac1x\dfrac{\mathrm d^2y}{\mathrm dt^2}

so that

\dfrac{\mathrm d^2y}{\mathrm dt^2}-\dfrac{\mathrm dy}{\mathrm dt}=x^2\dfrac{\mathrm d^2y}{\mathrm dx^2}

Then the ODE in terms of t is

\dfrac{\mathrm d^2y}{\mathrm dt^2}+8\dfrac{\mathrm dy}{\mathrm dt}-20y=0

The characteristic equation

r^2+8r-20=(r+10)(r-2)=0

has two roots at r=-10 and r=2, so the characteristic solution is

y_c(t)=C_1e^{-10t}+C_2e^{2t}

Solving in terms of x gives

y_c(x)=C_1e^{-10\ln x}+C_2e^{2\ln x}\implies\boxed{y_c(x)=C_1x^{-10}+C_2x^2}

4 0
3 years ago
If f(x) varies directly with x2, and f(x) = 96 when x = 4, find the value of f(2). 192 72 32 24
stepan [7]
F ( x ) = k * x²
f ( 4 ) = 96
96 = k * 4²
96 = 16 k
k = 96 : 16
k = 6
f ( 2 ) = 6 * 2² = 6 * 4 = 24
ANSWER D
5 0
3 years ago
Read 2 more answers
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