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3 years ago

Reviewing Dot Plots

Mathematics

2 answers:

MakcuM [25]3 years ago

8 0

Answer: A,B,D,E,F

A dot plot displays data values as dots above a number line.

Dot plots show the frequency with which a specific item appears in a data set.

There were 0 runs in 2 of the games.

Dot plots show the distribution of the data.

There were a total of 19 games.

slava [35]3 years ago

6 0

Answer:a,b,d,e,f.

Step-by-step explanation:hope it helps someone.

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Darlene kicks a soccer ball off the ground and in the air, with an initial velocity of 34 feet per second. using the formula h(t

monitta

Answer:

18.1 is the answer. I am glad I could help.

7 0

3 years ago

Read 2 more answers

What is the slope of the line that contains the point (13,-2) and (3,-2)

ra1l [238]

The slope of the line that contains the point (13,-2) and (3,-2) is 0

Solution:

Given that we have to find the slope of the line

The line contains the point (13,-2) and (3,-2)

The slope of line is given as:

$m = \frac{y_2-y_1}{x_2-x_1}$

Where, "m" is the slope of line

Here given points are (13,-2) and (3,-2)

$(x_1, y_1) = (13, -2)\\\\(x_2, y_2) = (3, -2)$

Substituting the values in formula, we get,

$m = \frac{-2-(-2)}{3-13}\\\\m = \frac{-2+2}{3-13}\\\\m = 0$

Thus the slope of line is 0

3 0

3 years ago

Two trains, Train A and Train B weigh a total of 349 tons. Train A is heavier than Train B. The difference in their weights is 2

Ainat [17]

Answer:

Train A = 299 tons Train B = 50 tons

Step-by-step explanation:
Train A = x

Train B = y

x+y = 349

x= y +249

Plug in one equation into another

y+249+y= 349

Simplify

2y+249=349

Subtract 249 from both sides

2y=100

Divide both sides by 2

y=50

Plug it into the x equation to solve for x

x+50=349

-50 from both sides

x=299

3 0

3 years ago

Suppose that a large mixing tank initially holds 100 gallons of water in which 50 pounds of salt have been dissolved. Another br

Serggg [28]

Answer:

dA/dt = 12 - 2A/(100 + t)

Step-by-step explanation:

The differential equation of this problem is;

dA/dt = R_in - R_out

Where;

R_in is the rate at which salt enters

R_out is the rate at which salt exits

R_in = (concentration of salt in inflow) × (input rate of brine)

We are given;

Concentration of salt in inflow = 4 lb/gal

Input rate of brine = 3 gal/min

Thus;

R_in = 4 × 3 = 12 lb/min

Due to the fact that solution is pumped out at a slower rate, thus it is accumulating at the rate of (3 - 2)gal/min = 1 gal/min

So, after t minutes, there will be (100 + t) gallons in the tank

Therefore;

R_out = (concentration of salt in outflow) × (output rate of brine)

R_out = [A(t)/(100 + t)]lb/gal × 2 gal/min

R_out = 2A(t)/(100 + t) lb/min

So, we substitute the values of R_in and R_out into the Differential equation to get;

dA/dt = 12 - 2A(t)/(100 + t)

Since we are to use A foe A(t), thus the Differential equation is now;

dA/dt = 12 - 2A/(100 + t)

5 0

3 years ago

Pls solve for x & explain your answer. x^5 + 10x^3 + 20x - 4 = 0

yarga [219]

Answer:

0.2

Step-by-step explanation:

Graph each side of the equation. The solution is the x-value of the point of intersection.

7 0

2 years ago