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vladimir1956 [14]
3 years ago
13

If the price of 23 toys is Rs. 276, then what will the price (Rs.) of 12 toys?

Mathematics
1 answer:
nata0808 [166]3 years ago
3 0

Answer:

price of 23 toys=Rs276

price of 1 toys=Rs276/23 =Rs 12

price of 12 toys = Rs 12*12 =Rs 144

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Y=x^2-6x-16 in vertex form
satela [25.4K]

Answer:

y=(x-3)^{2} -25

Step-by-step explanation:

The standard form of a quadratic equation is y=ax^{2} +bx+c

The vertex form of a quadratic equation is y=a(x-h)^{2} +k

The vertex of a quadratic is (h,k) which is the maximum or minimum of a quadratic equation. To find the vertex of a quadratic, you can either graph the function and find the vertex, or you can find it algebraically.

To find the h-value of the vertex, you use the following equation:

h=\frac{-b}{2a}

In this case, our quadratic equation is y=x^{2} -6x-16. Our a-value is 1, our b-value is -6, and our c-value is -16. We will only be using the a and b values. To find the h-value, we will plug in these values into the equation shown below.

h=\frac{-b}{2a} ⇒ h=\frac{-(-6)}{2(1)}=\frac{6}{2} =3

Now, that we found our h-value, we need to find our k-value. To find the k-value, you plug in the h-value we found into the given quadratic equation which in this case is y=x^{2} -6x-16

y=x^{2} -6x-16 ⇒ y=(3)^{2} -6(3)-16 ⇒ y=9-18-16 ⇒ y=-25

This y-value that we just found is our k-value.

Next, we are going to set up our equation in vertex form. As a reminder, vertex form is: y=a(x-h)^{2} +k

a: 1

h: 3

k: -25

y=(x-3)^{2} -25

Hope this helps!

3 0
3 years ago
Question 2 Not yet answered Points out of 2
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Answer:

Trapezoid

Step-by-step explanation:

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please mark me brainliest!

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Answer:

Step-by-step explanation:

\overrightarrow{a}=2*\overrightarrow{i}+3*\overrightarrow{j}\\\\||\overrightarrow{a}||=\sqrt{2^2+3^2} =\sqrt{13} \\\\\boxed{\overrightarrow{v}=\dfrac{20}{\sqrt{13}}*\overrightarrow{i}+\dfrac{30}{\sqrt{13}}*\overrightarrow{j}} \\\\\\||\overrightarrow{a}||=\sqrt{(\dfrac{20}{\sqrt{13}})^2+(\dfrac{30}{\sqrt{13}})^2} =\sqrt{\dfrac{400+900}{13} }==\sqrt{\dfrac{1300}{13} }=\sqrt{100}=10 \\

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