All categories

3 years ago

What is the upper and lower quartile of this set of data? 15, 19, 20, 25, 31, 38, 41

Mathematics

2 answers:

morpeh [17]3 years ago

4 0

Answer:

Lower Quartile (Q1) = 19; Upper Quartile (Q3) = 38.

Step-by-step explanation:

To find the quartiles, we begin by finding the median (Q2). The median is the middle value; this is 25.

The median splits the data into half. The median of the lower half is 19; this is the lower quartile. The median of the upper half is 38; this is the upper quartile.

aev [14]3 years ago

3 0

Answer:

Upper quartile: 38
Lower quartile: 19

You might be interested in

Please help vvvvvvvvvvv

Anuta_ua [19.1K]

Answer:

Step-by-step explanation:

since you are subtracting a negative number it reverses, so you actually ADD the two together

so, 12 1/2 + 4 1/2

add the whole numbers first;

12+4=16

then fractions:

1/2 + 1/2= 1

then all together;

16+1=17!

7 0

3 years ago

Question 1

777dan777 [17]

Answer:

There would be 94 tiles.

Step-by-step explanation:

The number of tiles is given by the following equation:

$n = 6 + 4p$

In which p is the current position.

How many tiles would there be in position 22?

This is n when $p = 22$ . So

$n = 6 + 4*22 = 6 + 88 = 94$

There would be 94 tiles.

8 0

3 years ago

Is there a greatest positive integer? If so, what is it? If not, why not?

balu736 [363]

No, there is no 'greatest integer'. That is because positive numbers can go up tp infinite, and we do not know where numbers stop.

However, there is a negative greatest integer because the ones that's closes to zero is -1.

3 0

3 years ago

Read 2 more answers

Team A has 12 more points than team b team A has 5 times as much points as team b

tekilochka [14]

Answer:

make no sense

6 0

3 years ago

I need help with this problem and show your work plz thanks

coldgirl [10]

Well is just their sum, thus

$\bf \cfrac{3}{4}+\cfrac{2}{3}\impliedby \stackrel{LCD~is}{12}\implies \cfrac{(3)3+(4)2}{12}\implies \cfrac{9+8}{12}\implies \cfrac{17}{12}\implies 1\frac{5}{12}$

5 0

3 years ago