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4 years ago

How do you do #33? According to this book, the answer is A) 0. I have no idea how to get that answer.

Mathematics

1 answer:

KATRIN_1 [288]4 years ago

5 0

$\bf 2a+3b=2b\implies 2a+3b-2b=0\implies 2a+1b=0
\\\\\\
6a+3b\iff 3(2a+1b)\iff 6a+3b\qquad 
\begin{cases}
2a+1b=0\\
thus\\
3(2a+1b)\\
3(0)\iff 0
\end{cases}$

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1. What is the value of the expression 3^-4?. a) -81. b) -12. c) -1/81. d) 1/81. 2. What is the value of the expression 1/4^3?.

hjlf

Answer:

Option d is correct

Option c is correct

Option a is correct

Option d is correct

Option c is correct

Explanation:

Using exponent rule:

$a^{-n} = \frac{1}{a^n}$

Given the expression:

$3^{-4}$

Apply the exponent rules:

$\frac{1}{3^4} = \frac{1}{81}$

Therefore, the value of the given expression is, $\frac{1}{81}$ .

To find the value of the expression $\frac{1}{4^3}$

then;

$\frac{1}{4^3} = \frac{1}{64}$

Therefore, the value of the given expression is, $\frac{1}{64}$ .

Find the the value of the expression $\frac{2}{4^3}$

then;

$\frac{2}{4^3} = \frac{2}{64}$

Simplify:

$\frac{1}{32}$

Therefore, the value of the given expression is, $\frac{1}{32}$ .

Given the expression:

$K^{-3} = \frac{1}{27}$

we can write this as:

$K^{-3} = \frac{1}{3^3}$

Apply the exponent rules:

$K^{-3} = 3^{-3}$

On comparing both sides we have;

K = 3

Therefore, the value of K is, 3

Given the expression:

$3^N= \frac{1}{81}$

we can write this as:

$3^N= \frac{1}{3^4}$

Apply the exponent rules:

$3^N = 3^{-4}$

On comparing both sides we have;

N = 4

Therefore, the value of N is, -4

3 0

4 years ago

Read 2 more answers

Khan academy need help with this

rewona [7]

Step-by-step explanation:

6 * 1 = 6

this means the circle can fit with 6 arcs each one of them has a length of 1.

so,

360° / 6 = 60° (Central angle for each arc)

8 0

3 years ago

Plss help meee

Alborosie

Step-by-step explanation:

Storage Space of Shed = Volume of Shed.

Volume of Shed = Volume of Rectangular level

+ Volume of Triangular roof

Volume of Rectangular Level =

Length x Width x Height

$12 \times 6 \times 8 \\ = 576 {ft}^{3}$

Volume of Triangular Roof =

Area of Triangular side x Length

$\frac{1}{2} \times base \times height \times length \\ = \frac{1}{2} \times 6 \times 4 \times 12 \\ = \frac{1}{2} \times 288 \\ = 144 {ft}^{3}$

Volume of Shed = 576 + 144

$720 {ft}^{3}$

3 0

3 years ago

Match the function with its graph. a. 1C, 2B, 3D, 4A c. 1D, 2A, 3C, 4B b. 1A, 2D, 3B, 4C d. 1A, 2B, 3C, 4D Please select the bes

oksano4ka [1.4K]

Answer:

The correct answer is "Option C".

Step-by-step explanation:

Given:

$\bold{ 1) y= -\tan (x- \frac{\pi}{2})}\\\\\bold{ 2) y= \tan (x+ \frac{\pi}{2})}\\\\\bold{ 3) y= -\cot (x- \frac{\pi}{2})}\\\\\bold{ 4) y= \cot (x+ \frac{\pi}{2})}\\\\$

solve the above equation:

$\Rightarrow 1) \ y= -\tan (x- \frac{\pi}{2})\\\\\Rightarrow \ y= \tan (\frac{\pi}{2}-x)\\\\\Rightarrow \ y= \cot x \ \ \ \ \ \bold{ that \ matchs \ graph \ D}\\\\ \Rightarrow 2) \ y= \tan (x+ \frac{\pi}{2})\\\\\Rightarrow \ y= - \cot x \ \ \ \ \bold{ that \ matchs \ graph \ A}\\\\$

$\Rightarrow 3) \ y= -\cot (x- \frac{\pi}{2})\\\\\Rightarrow \ y=\cot ( \frac{\pi}{2}-x)\\\\\Rightarrow \ y=\tan x\ \ \ \ \bold{that \ matchs \ graph \ C}\\\\$

$\Rightarrow 4) \ y= \cot (x+ \frac{\pi}{2})\\\\\Rightarrow \ y= \cot (\frac{\pi}{2}+x)\\\\\Rightarrow \ y= \ -tan x \ \ \ \ \ \bold{ that \ matchs \ graph \ A}$

The final answer is "Option C".

8 0

4 years ago

What is (are) the solution(s) to the equation 23x−3=−13x−6?

solniwko [45]

From Question ,
23x-3 = 13x-6
Or, 23x-13x = -6+3
Or, 10x = -3
Or, x = -3/10
Therefore x = -3/10 ans

Hope this helps !

Please mark it as the brainliest

6 0

3 years ago