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Ierofanga [76]
3 years ago
6

What is the solution to the nearest tenth to the equation below? 0.3y=-2

Mathematics
1 answer:
exis [7]3 years ago
7 0

[] Answer []

Y = -20 / 3

[] Explanation \ Evidence []


Multiply both sides by 10:

0.3y * 10 = -2 * 10


Refine:

3y = -20


Divide both sides by 3:

3y / 3 = -20 / 3


Simplify:

Y = -20/3


Check your work:

0.3 * -20/3 = -2


<> Eclipsed <>


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We multiply both numerator and denominator of the first fraction by 3 and we sum the two fractions:

1=\dfrac{3}{3n^2}+\dfrac{n^2-4n-5}{3n^2} = \dfrac{n^2-4n-2}{3n^2}

We multiply both sides by 3n^2:

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We move everything to one side and solve the quadratic equation:

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