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anyanavicka [17]
3 years ago
8

Help meeeeeeeeeeeeeeeeeeeeee

Mathematics
1 answer:
hodyreva [135]3 years ago
5 0

Answer:

people went to Bonnaroo

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Evaluate the expresion<br> 27+6x2+3/6
SSSSS [86.1K]
Exact Form: \frac{79}{2}


Decimal Form: 39.5


Mixed Number Form: 39\frac{1}{2}
5 0
3 years ago
2x + 6 = 20<br> Please answer quickly options for x are 6,7,5,8 they are one of those numbers
BaLLatris [955]

Answer: X = 7

Step-by-step explanation:

Or, you don't have to plug any of those in and solve for x

subtract 6 from both sides

2x = 14

divide 14 by 2x

x=7

5 0
3 years ago
PLZ HELP ITS DUEEE RNNNNN!!!!
Dimas [21]

Answer:

answer that do not poru branly

Step-by-step explanation:

hahahaahahahahha

4 0
2 years ago
Ben works for software company in Cleveland. To train new employees, Ben travels to their two other locations, Buffalo and Phila
Andru [333]

Answer:

Explanation:we will solve this question with help of linear programming.

Now,  let Ben goes x times in buffalo trip and goes y times in Philadelphia trip. Thus, according to the question, Min Z= 180x+300y

And s.t.r. 2x+3y≤105, where x≥5, y≥15.

since at (0,0) 0≤105(true), so area of 2x+3y≤105 will cover the origin.

But, 0≥5 and 0≥15 are false, so their area will not cover the origin.

Thus, after drawing the graph of these three lines we will get a feasible reason of triangle ABC, where point A≡(5,31.667), B≡(5,15), and C≡(30,15)

Z at A- 180×5+300×31.667=10,400.1

at B-180×5+300×15=1350( which is minimum.)

at C- 180×30+300×15=5,850

Thus, Ben should go 5 times to buffalo trip and 15 times to Philadelphia to minimize his cost which is $1350.




3 0
3 years ago
The region bounded by y=(3x)^(1/2), y=3x-6, y=0
Ganezh [65]

Answer:

4.5 sq. units.

Step-by-step explanation:

The given curve is y = (3x)^{\frac{1}{2} }

⇒ y^{2} = 3x ...... (1)

This curve passes through (0,0) point.

Now, the straight line is y = 3x - 6 ....... (2)

Now, solving (1) and (2) we get,

y^{2} - y - 6 = 0

⇒ (y - 3)(y + 2) = 0

⇒ y = 3 or y = -2

We will consider y = 3.

Now, y = 3x - 6 has zero at x = 2.

Therefor, the required are = \int\limits^3_0 {(3x)^{\frac{1}{2} } } \, dx - \int\limits^3_2 {(3x - 6)} \, dx

= \sqrt{3} [{\frac{x^{\frac{3}{2} } }{\frac{3}{2} } }]^{3} _{0} - [\frac{3x^{2} }{2} - 6x ]^{3} _{2}

= [\frac{\sqrt{3}\times 2 \times 3^{\frac{3}{2} }  }{3}] - [13.5 - 18 - 6 + 12]

= 6 - 1.5

= 4.5 sq. units. (Answer)

7 0
3 years ago
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