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Reptile [31]
3 years ago
5

It costs $50 to rent a car plus $3.00 per gallon of gas in the car. Sue can spend at most $86.00 total, so what's the most amoun

t of gallons of gas she can get when she rents the car?
1.Write the inequality (ex. a + bx ≤ c) and show all work to solve the inequality.

2. Explain what your solution means in the context of the problem. (Hint: What's the most amount of gallons Sue can get?)

3. If you were to graph this on a number line would you shade left or right?
Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
4 0

Answer:

i just know you can have 12 gallons of gas

Step-by-step explanation:

because it is 3x2=6

3x10=30 which means 10+2=12

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Answer:

Step-by-step explanation:

Simple interest is

I=Prt, where I= interest, P=principle (initial value), r=interest rate, t=time

I=200(0.052)3

I=$31.20

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Subract (8x+6)-(x+4)
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4 0
3 years ago
Can I get some help, it is due in 15 minutes and I need help. Thanks, any help appreciated
koban [17]

Well, I'm way past the 15 min mark, but here's how to do the question.


With this, you will need to use the distance formula, \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}, on XY, YZ, and ZX.



XY: \sqrt{(3-1)^2+(1-6)^2}


Firstly, solve inside the parentheses: \sqrt{(2)^2+(-5)^2}


Next, solve the exponents: \sqrt{4+25}


Next, solve the addition, and XY's distance will be √29



(The process is the same with the other 2 sides, so I'll go through them real quickly)


YZ:

\sqrt{(6-3)^2+(3-1)^2}\\ \sqrt{(3)^2+(2)^2}\\ \sqrt{9+4}\\ \sqrt{13}



ZX:

\sqrt{(1-6)^2+(6-3)^2}\\ \sqrt{(-5)^2+(3)^2}\\ \sqrt{25+9}\\ \sqrt{34}



Now that we got the 3 sides, we can add them up: \sqrt{29}+\sqrt{13} +\sqrt{34} =14.8


In short, your answer is 14.8, or the second option.

8 0
3 years ago
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