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Igoryamba
3 years ago
7

How do I solve for x??

Mathematics
2 answers:
Romashka-Z-Leto [24]3 years ago
8 0

Answer:

x=40

Step-by-step explanation:

The angles are vertical angles And vertical angles measure the same

so

120=3x

Divide both sides by 3:

x=40

timurjin [86]3 years ago
4 0

Answer:

x=40 degrees

Step-by-step explanation:

3x=120 (vertical angles)

solve: 3x=120

x=40

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Mary went on vacation from the uk to the us, so she had to purchase some dollars ($). how many pounds sterling (l) did she excha
kap26 [50]

Exchange rate L 1 = $ 1.5542

Mary has $ 135

Pounds that Mary exchanged 135/1.5542

= L 86.8614 = L 87

4 0
3 years ago
Prove that sinA-sin3A+sin5A-sin7A/cosA-cos3A-cos5A+cos7A= cot2A
MAVERICK [17]
Write the left side of the given expression as N/D, where
N = sinA - sin3A + sin5A - sin7A
D = cosA - cos3A - cos5A + cos7A
Therefore we want to show that N/D = cot2A.

We shall use these identities:
sin x - sin y = 2cos((x+y)/2)*sin((x-y)/2)
cos x - cos y = -2sin((x+y)/2)*sin((x-y)2)

N = -(sin7A - sinA) + sin5A - sin3A
    = -2cos4A*sin3A + 2cos4A*sinA
    = 2cos4A(sinA - sin3A)
    = 2cos4A*2cos(2A)sin(-A)
    = -4cos4A*cos2A*sinA

D = cos7A + cosA - (cos5A + cos3A)
   = 2cos4A*cos3A - 2cos4A*cosA
   = 2cos4A(cos3A - cosA)
   = 2cos4A*(-2)sin2A*sinA
   = -4cos4A*sin2A*sinA

Therefore
N/D = [-4cos4A*cos2A*sinA]/[-4cos4A*sin2A*sinA]
       = cos2A/sin2A
      = cot2A

This verifies the identity.
4 0
3 years ago
HELP PLEASE! The probability of drawing a penny from a bag of coins is 1/5. What is the probability of drawing a coin that is no
lutik1710 [3]
Okay so since with the penny it's 1/5 that means there's only one penny and 5 other coins and 100% is 5 then 80% will be 4 so your answer is 80% hope this helps

3 0
3 years ago
Read 2 more answers
8 is 2% of what number
bixtya [17]
The answer would be 16. 
8+8=16 
5 0
3 years ago
Read 2 more answers
Simplify. Your answer should contain only positive exponents with no fractional exponents in the denominator.
mart [117]

Answer:

\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}.

Step-by-step explanation:

The given expression is  

\dfrac{3y^{\frac{1}{4}}}{4x^{-\frac{2}{3}}y^{\frac{3}{2}}\cdot 3y^{\frac{1}{2}}}

We need to simplify the expression such that answer should contain only positive exponents with no fractional exponents in the denominator.

Using properties of exponents, we get

\dfrac{3}{4\cdot 3}\cdot \dfrac{y^{\frac{1}{4}}}{x^{-\frac{2}{3}}y^{\frac{3}{2}+\frac{1}{2}}}    [\because a^ma^n=a^{m+n}]

\dfrac{1}{4}\cdot \dfrac{y^{\frac{1}{4}}}{x^{-\frac{2}{3}}y^{2}}

\dfrac{1}{4}\cdot \dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{y^{2}}         [\because a^{-n}=\dfrac{1}{a^n}]

\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}

We can not simplify further because on further simplification we get negative exponents in numerator or fractional exponents in the denominator.

Therefore, the required expression is \dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}.

5 0
3 years ago
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