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4 years ago

15

Every night, John spends 2 hours doing homework, 30 minutes eating, and 45 minutes playing outdoors. How many minutes does he sp

end on these activities?

2 answers:

bazaltina [42]4 years ago

5 0

195 mins is how long he spends

boyakko [2]4 years ago

3 0

Answer: 195 mins

Explanation: there is none

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Evaluate the line integral, where C is the given curve. (x + 6y) dx + x2 dy, C C consists of line segments from (0, 0) to (6, 1)

Dima020 [189]

Split $C$ into two component segments, $C_1$ and $C_2$ , parameterized by

$\mathbf r_1(t)=(1-t)(0,0)+t(6,1)=(6t,t)$

$\mathbf r_2(t)=(1-t)(6,1)+t(7,0)=(6+t,1-t)$

respectively, with $0\le t\le1$ , where $\mathbf r_i(t)=(x(t),y(t))$ .

We have

$\mathrm d\mathbf r_1=(6,1)\,\mathrm dt$

$\mathrm d\mathbf r_2=(1,-1)\,\mathrm dt$

where $\mathrm d\mathbf r_i=\left(\dfrac{\mathrm dx}{\mathrm dt},\dfrac{\mathrm dy}{\mathrm dt}\right)\,\mathrm dt$

so the line integral becomes

$\displaystyle\int_C(x+6y)\,\mathrm dx+x^2\,\mathrm dy=\left\{\int_{C_1}+\int_{C_2}\right\}(x+6y,x^2)\cdot(\mathrm dx,\mathrm dy)$

$=\displaystyle\int_0^1(6t+6t,(6t)^2)\cdot(6,1)\,\mathrm dt+\int_0^1((6+t)+6(1-t),(6+t)^2)\cdot(1,-1)\,\mathrm dt$

$=\displaystyle\int_0^1(35t^2+55t-24)\,\mathrm dt=\frac{91}6$

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3 years ago

Sam ran at 6km/h for two hours 20 minutes what distance did he run?

horrorfan [7]

He ran 14 km, multiply 6 by 2 and 1/3.

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3 years ago

What should be multiplied by the expression in the image to obtain the smallest square

makkiz [27]

Answer:

2xy

Step-by-step explanation:

Here, we want to obtain the number with the smallest square

To get this, we simply find the nearest number square which is 2

The nearest x squared which is x (to get x^4)

The nearest y squared which is y (to get y^2)

Thus, the smallest number so we get a square will be; 2xy

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3 years ago

Pls help me with i have no help pt 2

ioda

Answer:

2

Step-by-step explanation:

2

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2 years ago

Read 2 more answers

-7y = -77 solve for y

babunello [35]

Y=11
is the answer to your question! <3

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3 years ago

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