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Lemur [1.5K]
3 years ago
15

U = {p, q, r, s, t, u, v, w}

Mathematics
1 answer:
SOVA2 [1]3 years ago
7 0

Answer:

{p, q, u, v, w}

Step-by-step explanation:

Please mark me bainliest if I helped!

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Daniel is selecting a sock from his drawer.
Firdavs [7]

Answer:2/10

Step-by-step explanation:

2/10

7 0
3 years ago
Please explain also​
Katena32 [7]

Answer:

300 m^2

Step-by-step explanation:

If you have any questions about the way I solved it, don't hesitate to ask =)

3 0
3 years ago
What is equivalent to 2/5?
zhuklara [117]
As in decimal it would be 0.4 but if you want a fraction it could be 4/10

3 0
3 years ago
What reasoning and explanations can be used when solving radical equations and how do extraneous solutions arise from radical eq
Mkey [24]

Answer:

We know that, a 'radical equation' is an equation that contains radical expressions, which further are the expressions containing radicals ( square roots and other roots of numbers ).

In order to solve radical equations, we use the rules of exponents and basic algebraic properties.

The common reasoning to use while solving a radical equation is:

1. Isolate the radical expression.

2. Square both sides of the equation to remove radical.

3. After removing the radical, solve the equation to find the unkown variable

4. Check the answer for the errors occurred by removing the radicals.

For e.g. \sqrt{x}-3=5

i.e. \sqrt{x}-3+3=5+3 ( Adding 3 on both sides )

i.e. \sqrt{x}=8

i.e. (\sqrt{x})^{2} =8^{2}

i.e. x=64.

So, the solution the the radical equation \sqrt{x}-3=5 is x = 64.

Further, we know that an 'extraneous solution' is that root of the radical equation which is not a root of the original equation and is excluded from the domain.

for e.g. Take \sqrt{x+4} =x-2

i.e. (\sqrt{x+4})^{2} =(x-2)^2

i.e. x+4=x^2+4-4x

i.e. 0=x^2-5x

i.e. 0=x(x-5)

i.e. x = 0 and x = 5.

Substituting x = 0 in \sqrt{x+4} =x-2, gives \sqrt{0+4} =0-2 i.e. \sqrt{4} =-2 i.e. 2=-2, which is not possible.

So, x = 0 is a solution that does not satisfy the equation.

Hence, x = 0 is an extraneous solution.

7 0
4 years ago
A bakery uses 3/4 cups of oats to make a 2 4/7 pounds of oatmeal cookies.how many cups of oats are required per pound of cookies
Flura [38]
We can use ratios to find the answer to this.
Set up the ratio.
3/4 / 18/7 = x / 1

Multiply both sides by 1
3/4 / 18/7 = x

Inverse 18/7 to 7/18 so we can multiply.
3/4 * 7/18 = x
Multiply.
21/72 = x
Simplify7/24 = x
Therefore, 7/24 cups of oats is used per pound.
3 0
3 years ago
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