For this case we have the following expression:
y2 - xy - 56x2
Rewriting we have the factored expression, which is given by:
(7x + y) (y-8x)
Checking we have:
7xy - 56x ^ 2 + y ^ 2 - 8xy
y ^ 2 - xy - 56x ^ 2 (OK)
Answer:
The factored expression is given by:
y2 - xy - 56x2 = (7x + y) (y-8x)
Answer: Hi!
First, we should combine like terms:
4b + 5b = 8b − 1 +3b + 15 =
9b = 11b + 14
Now, we should subtract 11b from both sides.
-2b = 14
Now, we should divide both sides by -2.
b = -7
Hope this helps!
Answer:
Step-by-step explanation:
- log 2x + log (x - 5) = 2
- log (2x(x - 5)) = 2
- 2x(x - 5) = 10²
- 2(x² - 5x) = 100
- x² - 5x - 50 = 0
- x² + 5x - 10x - 50 = 0
- x(x + 5) - 10(x + 5) = 0
- (x - 10)(x + 5) = 0
- x = 10
- x = -5, this root is discounted as log should be positive.
Correct choice is 3.
The two angles form a straight line which is equal to 180 degrees. This makes the angles supplemtary.
To find x, add the two angles together to equal 180:
7x + x+20 = 180
Combine like terms:
8x + 20 = 180
Subtract 20 from both sides:
8x = 160
Divide both sides by 8:
X = 20
Answer:
- The function f(x) = 9,000(0.95)^x represents the situation.
- After 2 years, the farmer can estimate that there will be about 8,120 bees remaining.
- The range values, in the context of the situation, are limited to whole number
Step-by-step explanation:
The "growth" rate is -5%, so the growth factor, the base in the exponential equation, is 1.00-5% =0.95.
Using x=2, we find the population in 2 years is expected to be about ...
f(2) = 9000·0.95^2 ≈ 8123 . . . . about 8120
Using x=4, we find the population in 4 years is expected to be about ...
f(4) = 9000·0.95^4 ≈ 7331 . . . . about 7330
Since population is whole numbers of bees, the range of the function is limited to whole numbers.
The domain of the function is numbers of years. Years can be divided into fractions as small as you want, so the domain is not limited to whole numbers.
The choices listed above are applicable to the situation described.