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viktelen [127]
3 years ago
9

Perform the operation indicated, then place the answer in the proper location on the grid. The perimeter of a triangle is 7a - 1

1b. If two of its sides are 2a + b and a - 9b, what is the third side?

Mathematics
1 answer:
vlada-n [284]3 years ago
3 0

Answer: 4 a - 3 b

Step-by-step explanation:

Since, the perimeter of the triangle = sum of all the three side of the triangle.

Here, two sides of the triangle are 2a + b and a - 9b,

And, the perimeter of the triangle = 7 a - 11

Let third side = x

Therefore, 2 a + b + a - 9 b + x = 7 a - 11 b

⇒ 3 a - 8 b + x = 7 a - 11 b

⇒ x = 7 a - 11 b - 3 a + 8 b

⇒ x = 4 a - 3 b  ( by operating like terms)

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If you observe that 16 = 2^4, you can rewrite the expression as

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Now, if you use the exponent rule (a^b)^c = a^{bc}, you may rewrite the expression again:

(2^4)^{\frac{1}{4}} = 2^{4\cdot\frac{1}{4}} = 2^1 = 2

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6 0
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8 0
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Perform the indicated operation. -6 + (-5) + 7
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5 0
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1/7 ÷ 2 =
e-lub [12.9K]

Hey there!

1/7 ÷ 2

= 1/7 ÷ 2/1

1/7 ÷ 2/1

Revert 2/1 to 1/2

1 × 1 / 7 × 2

1 × 1 = 1 ⬅ your NUMERATOR (top number)

7 × 2 = 14 ⬅ your DENOMINATOR (bottom number)

1(1) / 7(2) = 1/14

Answer: 1/14 ✅

Good luck on your assignment and enjoy your day!

~LoveYourselfFirst:)

5 0
3 years ago
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