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viktelen [127]
3 years ago
9

Perform the operation indicated, then place the answer in the proper location on the grid. The perimeter of a triangle is 7a - 1

1b. If two of its sides are 2a + b and a - 9b, what is the third side?

Mathematics
1 answer:
vlada-n [284]3 years ago
3 0

Answer: 4 a - 3 b

Step-by-step explanation:

Since, the perimeter of the triangle = sum of all the three side of the triangle.

Here, two sides of the triangle are 2a + b and a - 9b,

And, the perimeter of the triangle = 7 a - 11

Let third side = x

Therefore, 2 a + b + a - 9 b + x = 7 a - 11 b

⇒ 3 a - 8 b + x = 7 a - 11 b

⇒ x = 7 a - 11 b - 3 a + 8 b

⇒ x = 4 a - 3 b  ( by operating like terms)

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The equations below represent the numbers y of tickets sold after x weeks for two different local music festivals.
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Answer:

x=3.5

Step-by-step explanation:

if y = y

20x+115=10x+150

-10x        -10x

10x+115=150

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10x=35

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3 years ago
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Given the set points K+1:(-1,8),(1,0) and (2,5), find the quadratic polynomial interpolate
Sauron [17]

Answer:

The interpolating polynomial is p(x) = 1-4x+3x^2.

Step-by-step explanation:

We want to find a quadratic polynomial p(x) such that p(-1)=8, p(1)=0 and p(2)=5. In order to do this let us write p(x) = a_0+a_1x+a_3x^2.

Now, evaluating the polynomial in the points -1, 1 and 2 we get

\begin{cases} 8 = p(-1) &= a_0-a_1+a_2\\ 0 = p(1) &= a_0+a_1+a_2\\ 5 = p(2) &= a_0+2a_1+4a_2\end{cases}

This relations give us a linear system of equations:

\begin{cases} 8 &= a_0-a_1+a_2\\ 0 &= a_0+a_1+a_2\\ 5&= a_0+2a_1+4a_2\end{cases}

where the a_0, a_1 and a_2 are the unknowns.

The augmented matrix of the system is

\begin{pmatrix}1 & -1 & 1 & 8\\ 1 & 1 & 1 & 0\\ 1 & 2 & 4 & 5\end{pmatrix}

In this matrix it is easy to eliminate the 1's of the first column and get

\begin{pmatrix} 1 & -1 & 1 & 8\\ 0 & 2 & 0 & -8\\ 0 & 3 & 3 & -3\end{pmatrix}

From this matrix we can find the values of each unknown. Notice that the second row gives us 2a_2=-8 that yields a_1=-4.

Then, the third row means 3a_1+3a_2=-3 that gives -12+3a_2=-3. So, a_2=3.

Finally, the first row is a_0-a_1+a_2=8 and substituting is a_0+7=8 that yields a_0=1.

Therefore, the interpolating polynomial is

p(x) = 1-4x+3x^2.

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3 years ago
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7,000 x 1/1000 = 7,000/1,000 = 7

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