what effect does doubling the radius of a cone have on the volume of the cone if the height remains the same

1 answer:

4 0

V=(1/3)hpir^2
lets say this is original, undoubled volume
so o=v=(1/3)hpir^2

so for new volume, or n, that is r to 2r, doubled radius
n=(1/3)hpi(2r)^2
n=(1/3)hpi4r^2
n=4((1/3)hpir^2)
remmember that o=(1/3)hpir^2
n=4(o)

it is 4 times the old one

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Step-by-step explanation:

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------------

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2 years ago

Calculate dy/dx You need not expand your answer. y=3x^2-9x+13/2x+4 ...?

grandymaker [24]

The solution to the problem is as follows:

The quotient rule is ( f'(x)g(x)-f(x)g'(x) )/ (g(x))^2 {complex written on 1 line I know}

let f(x)=9x +13 and g(x)=2x+4

f'(x)=9 and g'(x)=2 

therefore just substitute the equations in. 

y'= 6x - ((9(2x+4)-2(9x+13))/((2x+4)^2))


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3 years ago

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lakkis [162]

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-5x + -7x = 0 + -96

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Use x to solve for y:

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Add 40 to both sides and divide by 8:

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