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Yuliya22 [10]
3 years ago
7

In the expression 27 ÷ 9 x 3 – 4 x 2, explain why 27 ÷ 9 is the first operation you would do

Mathematics
2 answers:
hichkok12 [17]3 years ago
4 0

Answer:

Order of operations

Step-by-step explanation:

In order of operations, multiplication and division go first of the things in this equation (remember PEMDAS?), after that it's left-right. So the first division left-right is 27/9

katovenus [111]3 years ago
3 0
Because you do x or ÷ before + or -. but if you have both x and ÷ then you do whichever is first
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Help me please. <br> F(x) = 4 - 3x <br> f(10) =
tigry1 [53]

Answer:

f(10) = - 26

Step-by-step explanation:

To evaluate f(10), substitute x = 10 into f(x), that is

f(10) = 4 - 3(10) = 4 - 30 = - 26

8 0
3 years ago
Question 1<br> Find the absolute value of each integer.<br> a. 141 =<br> b. l-12] =<br> c./-212=
Vilka [71]

Answer:

is it a test and what is the lesson name called?

Step-by-step explanation:

5 0
2 years ago
What is the y value of the vertex of the function f(x)=-(x-3)(x+11)
AnnyKZ [126]

Answer:

49

Step-by-step explanation:

Because there is a minus sign infront of x-3, we can convert x-3 into the negative form:

- * x

- * -3

-x + 3

Which gives us:

(-x + 3)(x + 11)

Now expand the brackets with the formula:

(a + b)(c + d) = ac + ad + bc + bd

-x * x = -x²

-x * 11 = -11x

3 * x = 3x

3 * 11 = 33

-x² - 11x + 3x + 33

-x² - 8x + 33

The formula for finding the x coordinate of a vertex in a quadratic equation is:

x = \frac{-b}{2a}

Plug known variables in:

x = \frac{-(-8)}{2(-1)}

x = \frac{8}{-2}

x = -4

Now, to find the y coordinate, plug this variable back into the quadratic equation:

-x² - 8x + 33

y = -(-4^2) - (32) + 33\\y = -16 + 32 + 33\\\\

y = 49

So the y coordinate of the vertex is 49.

Hope this helps!

4 0
3 years ago
Which of the following polygons is not a regular polygon?​
Rus_ich [418]

Answer: the rectangular

Step-by-step explanation:

All the sides are equal for a regular polygon

7 0
2 years ago
Read 2 more answers
If f(x) = x2 – 1 and g(x) = 2x – 3, what is the domain of (f circle g) (x)? (negative infinity, infinity) Left-bracket negative
n200080 [17]

Answer:

A. (-∞, ∞)

Step-by-step explanation:

f circle g (x) is another way of expressing f(g(x)). Basically, we have to plug g(x) into f(x) wherever we see x's.

f(x) = x^2 - 1

f(x) = (2x-3)^2 - 1

Now find the domain. I think the easiest way to do this is to graph it. I've attached the graph. You can also do it algebraically by thinking about it: it's a positive parabola (+x^2) and its minimum is -1, so its range will not be all real numbers, but its domain will certainly be. (The range would be answer choice B!)

Domain = (-∞, ∞)

5 0
3 years ago
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