Samantha has a mass of 30 kg. What is her weight? 30 N 294 N 294 kg 30 kg
2 answers:
Samantha's weight is 294 N
Weight is the force of gravitational attraction acting on the person. The gravitational field strength <em>g </em>on Earth is the force experienced by a mass of 1 kg placed on the surface of the Earth and has a value 9.8 N/kg.
Therefore, the weight of a mass <em>m </em>is given by,
Substitute 30 kg for m and 9.8 N/kg for g.
Thus, Samantha's weight is 290 N
You might be interested in
Answer:
The ratio of the power generated by the engines are
(b) is correct option.
Explanation:
Given that,
Mass of Tesla = 2000 Kg
Torque = 400 Nm
Mass of Mercedes = 1.5 M Tesla
The Benz engine produces 50% more torque than the Tesla.
We need to calculate the power generated by the engines 6 seconds after a start from rest
Using formula of power
We know that,
Put the value of F and v in equation (I)
Here, r and t are same for both bodies.
We need to calculate the ratio of the power generated by the engines
Using formula of power
Put the value into the formula
Hence, The ratio of the power generated by the engines are
This question is incomplete, the complete question is;
Consider the cylindrical weir of diameter 3m and length 6m. If the fluid on the left has a specific gravity of 1.6 and on the right has a specific gravity of 0.8, Find the magnitude and direction of the resultant force.
Answer:
- the magnitude of the resultant force is 557.32 kN
- the direction of resultant force is 48.29°
Explanation:
Given the data in the question and the diagram below,
First we work on the force on the left hand side.
Left Horizontal
= βgAr
here, h = 3/2 = 1.5 m, β = 1.6, g = 9.81 m/s², A = 3 m × 6 m = 18 m²
we substitute
= βgAh = ( 1.6 × 1000 ) × 9.81 × 18 × 1.5 = 423792 N
Left Vertical
= ( βgπh² / 2 ) × W
we substitute
= [ ( ( 1.6 × 1000 ) × 9.81 × π(1.5)² ) / 2 ] × 6 = 332845.458 N
Now we go to the right hand side
Right Horizontal
= βgAh
here, h' = 1.5/2 = 0.75 m, β = 0.8, g = 9.81 m/s², A = 1.5 m × 6 m = 9 m²
we substitute
= ( 0.8 × 1000 ) × 9.81 × 9 × 0.75 ) = 52974 N
Right Vertical
= ( βgπh² / 4 ) × W
we substitute
= [ ( ( 0.8 × 1000 ) × 9.81 × π(1.5)² ) / 4 ] × 6 = 83211.36 N
Hence
Fx = -
= 52974 N - 423792 N = 370818 N
Fy = +
= 332845.458 N + 83211.36 N = 416056.818 N
R = √( Fx² + Fy² ) = √[ (370818 N)² + (416056.818 N)² ] = 557323.3 N
R = 557.32 kN
Therefore, the magnitude of the resultant force is 557.32 kN
Direction of resultant force;
tanθ = Fy / Fx
we substitute
tanθ = 416056.818 N / 370818 N
tanθ = 1.121997
θ = tan⁻¹( 1.121997 )
θ = 48.29°
Therefore, the direction of resultant force is 48.29°
