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Reil [10]
4 years ago
6

One end of a graphite rod is brought near a heat source. How does the other end of the rod eventually heat up? A. Directly from

the heat source B. Vibrations from neighboring atoms C. Waves from the heat source D. Waves from neighboring atoms
Physics
1 answer:
m_a_m_a [10]4 years ago
8 0

Answer:

Vibrations from neighboring atoms

Explanation:

When a rod is heated, the thermal energy transferred to the molecules of the rod causes them to vibrate faster. As the molecules near the heat source vibrate faster, they eventually transfer their excess energy to neighbouring molecules which also begin to vibrate faster. This continues until heat is distributed throughout the length of the rod.

The process described above is known as heat transfer by conduction.

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Although he did not present a mechanism, what were the key points of Alfred Wegener’s proposal for the concept of continental dr
valentinak56 [21]

Answer: Alfred Wegener provided some of the important points that supported the theory of continental drift. They are as follows-

  1. The continents were once all attached together, and this can be proved by studying the coastlines of some of the continents that perfectly matches with one another.
  2. The appearance of similar rock types and similar fossils (including both animals and plants) has also contributed much information that continents were once all together.
4 0
4 years ago
A 51.0 kg cheetah accelerates from rest to its top speed of 31.7 m/s. HINT (a) How much net work (in J) is required for the chee
andrey2020 [161]

(a) 2.56\cdot 10^4 J

The work-energy theorem states that the work done on the cheetah is equal to its change in kinetic energy:

W= \Delta K = \frac{1}{2}mv^2 - \frac{1}{2}mu^2

where

m = 51.0 kg is the mass of the cheetah

u = 0 is the initial speed of the cheetah (zero because it starts from rest)

u = 31.7 m/s is the final speed

Substituting, we find

W=\frac{1}{2}(51.0 kg)(31.7 m/s)^2 - \frac{1}{2}(51.0 kg)(0)^2=2.56\cdot 10^4 J

(b) 6.1 cal

The conversion between calories and Joules is

1 cal = 4186 J

Here the energy the cheetah needs is

E=2.56\cdot 10^4 J

Therefore we can set up a simple proportion

1 cal : 4186 J = x : 2.56\cdot 10^4 J

to find the equivalent energy in calories:

x=\frac{(1 cal)(2.56\cdot 10^4 J)}{4186 J}=6.1 cal

3 0
3 years ago
At 2:00 p.m. a car's speedometer reads 30 mi/h. At 2:30 p.m. it reads 50 mi/h. Show that at some time between 2:00 and 2:30 the
Gelneren [198K]

Answer:

The acceleration is exactly 40 mi/h² as shown

Explanation:

Given;

initial velocity of the car, u = 30 mi/h

final velocity of the car, v = 50 mi/h

change in velocity, ΔV = v - u

                               ΔV = 50 mi/h - 30 mi/h = 20 mi/h

initial time, t₁ = 2:00 PM

final time, t₂ = 2:30 PM

Change in time, Δt = t₂ - t₁

                           Δt = 2: 30 - 2:00 = 30 mins  = 0.5 hour

Acceleration is given as change in velocity per change in time;

a = ΔV /  Δt

a = \frac{20 \ mi/h}{0.5 \ h}\\\\a = 40 \ mi/h^2 \ (shown)\\\\

Therefore, the acceleration is exactly 40 mi/h² as shown.

6 0
3 years ago
The object has a redshift of 7.6 and the JWST observes the object at a wavelength of 2 microme-
olasank [31]

b. The wavelength of light emitted by the object is 233 nm

c. The type of radiation originally emitted by the object is ultraviolet radiation.

To find the wavelength, we need to know what redshift is.

<h3>What is redshift?</h3>

Redshift is the increase in wavelength and the corresponding decrease of frequency and photon energy of electromagnetic radiation.

Redshift is given by z = λ'/λ - 1 where

  • λ' = observed wavelength and
  • λ = emitted wavelength.

Making λ subject of the formula, we have

λ = λ'/(1 + z)

Given that has a redshift of 7.6 and the JWST observes the object at a wavelength of 2 micrometres (mid-infrared light).

So,

  • z = 7.6 and
  • λ' = 2μm

<h3>(b) What is the wavelength of the light emitted by the object?</h3>

Substituting the values of the variables into the equation, we have

λ = λ'/(1 + z)

λ = 2μm/(1 + 7.6)

λ = 2μm/8.6

λ = 0.233 μm

λ = 233 nm

So, the wavelength of light emitted by the object is 233 nm

<h3>c. What type of radiation was originally emitted by the object?</h3>

Since the wavelength is 233 nm and the wavelength is in the range of ultraviolet radiation 200 nm - 315 nm.

So, the type of radiation originally emitted by the object is ultraviolet radiation.

Learn more about redshift here:

brainly.com/question/27915180

#SPJ1

8 0
2 years ago
A wave transfers _____ from the source outward in the direction of wave motion.
DerKrebs [107]

A wave transfers energy from the source outward in the direction of wave motion.

To add, <span>in physics, a </span>wave<span> is an oscillation accompanied by a transfer of energy that travels through a medium (space or mass). Frequency refers to the addition of time.</span>

5 0
3 years ago
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