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elena55 [62]
3 years ago
9

Which of these would have the lowest albedo?

Physics
1 answer:
kati45 [8]3 years ago
3 0
All black surfaces is the correct answer
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Three people pull simultaneously on a stubborn donkey. Jack pulls directly ahead of the donkey with a force of 77.3 N, Jill pull
DiKsa [7]

Answer:

F_{net} = 232.8 N

towards right so it is -15 degree

Explanation:

Net force in forward direction due to all three is given as

F_x = F_1 + F_2cos45 + F_3cos45

here we know that

F_1 = 77.3 N

F_2 = 61.7 N

F_3 = 147 N

F_x = 77.3 + 61.7 cos45 + 147 cos45

F_x = 224.9 N

Similarly in Y direction we will have

F_y = F_3 sin45 - F_2 sin45

F_y = (147 - 61.7)sin45

F_y = 60.3 N

Now the net force on the donkey is given as

F_{net} = \sqrt{F_x^2 + F_y^2}

F_{net} = \sqrt{224.9^2 + 60.3^2}

F_{net} = 232.8 N

Now direction of force is given as

tan\theta = \frac{F_y}{F_x}

tan\theta = \frac{60.3}{224.9}

\theta = 15^o towards right so it is -15 degree

3 0
3 years ago
Why does the shape of the lens in your eye change?
Nina [5.8K]

The Lens Changes Shape to Focus Near Objects. Light rays from objects that are close to the eye are not parallel. Therefore, the eye must bend them more in order to focus the rays on the retina. To accomplish this, the lens change shape.

<h3>Hope this helps</h3>

3 0
3 years ago
Read 2 more answers
Charged objects have a _________ charge.<br>A) net, B) moving, C) positive, D) negative
marissa [1.9K]
C. positive, this is right because when something it is charged kinda how when you charge your phone it has energy now so that means it is positive but when its dead it is negative
5 0
3 years ago
If a→=3i^-2j^-k^ and b→=i^+4j^+k^, find a unit vector n^ normal to the plane containing a→ and b→ such that a→, b→ and n^, in th
Vladimir [108]

vector a = 3i - 2j - k and vector b = i + 4j + k, the unit vector, n, normal to the plane is (7i - j + 7k)/3√11

What is a vector?

A vector is a quantity having direction as well as magnitude.

Vectors can especially be used in determining the position of one point in space relative to another.

From the question,

The normal vector to the plane is c = a × b

we have that, a = 3i - 2j - k and b = i + 4j + k,

c = a × b

c = (3i - 2j - k) × (i + 4j + k)

= 3i × i + (- 2j) × i + (-k) × i + 3i × 4j + (- 2j) × 4j + (-k) × 4j + 3i × k + (- 2j) × k + (-k) × k

= 3i × i - 2j × i - k × i + 12i × j - 8j × j - 4k × 4j + 3i × k - 2j × k - k × k

It is known that

i × i = 0,

j × j = 0 and

k × k = 0.

we also have that

c = 3(0) - 2(-k) - (-j) + 12k - 8(0) - 16(-i) + 3(-j) - 2i - 0

c = 0 + 2k + j + 12k - 0 + 16i - 3j - 2i

c = 16i - 2i + j - 3j + 2k + 12k

c = 14i -2j + 14k

The unit vector normal to the plane n = c/ |c|

where |c| is the magnitude of c

= √(14² + (-2)² + 14²) = √(196 + 4 + 196)

= √396

= √(36 × 11)

= 6√11

we can write that n = c/|c|

= (14i -2j + 14k)/6√11

we simplify further

= 2(7i - j + 7k)/6√11

= (7i - j + 7k)/3√11

So, the unit vector normal to the plane is (7i - j + 7k)/3√11

Learn more about vectors at: brainly.com/question/25705666

#SPJ1

7 0
2 years ago
Knowing the speed of light (3x10m/s), calculate how long a
vivado [14]

Answer:

9.5 x 10^15 meters per year

Explanation:

So, you have:

\frac{300,000,000}{1} \frac{meters}{second}

We want the amount of meters light travels in one year. There are 3600 seconds in 1 hour, 24 hours in 1 day, and 365 days in a year. Using these conversion factors, we can set up some nice cancellations:

\frac{300,000,000}{1} \frac{meters}{second}\frac{3600}{1} \frac{seconds}{hour} \frac{24}{1} \frac{hours}{day} \frac{365}{1} \frac{days}{year}

Seconds will cancel, hours will cancel, days will cancel. We have meters per year:

300,000,000*3600*24*365\frac{meters}{year} =9.5x10^{15}\frac{meters}{year}

5 0
2 years ago
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