Answer:
Following are the answer to this question:
In question, a) ordinal.
In question, b) ratio
.
In question, c) true.
Step-by-step explanation:
For its "ordained" existence, regular data is used to conduct surveys and questionnaires. To identify respondents into different categories, a quantitative methodology is employed to sufficient excess.
Its ratio data is defined as a statistical method with the same features as continuous variables, that recognize the proportion of each data to an absolute null as its source. In many other words, the meaning of the line graph may not be positive.
Its newest program gives the gap between exits data.
Answer:
Step-by-step explanation:
![( \frac{625}{16} {)}^{ \frac{1}{4} } \\ \sqrt[4]{ \frac{625}{16} } = \frac{ \sqrt[4]{625} }{ \sqrt[4]{16} } \\ \frac{ \sqrt[4]{ {5}^{4} } }{ \sqrt[4]{16} } = \frac{ \sqrt[4]{ {5}^{4} } }{ \sqrt[4]{ {2}^{4} } } = \frac{5}{2}](https://tex.z-dn.net/?f=%28%20%5Cfrac%7B625%7D%7B16%7D%20%20%7B%29%7D%5E%7B%20%5Cfrac%7B1%7D%7B4%7D%20%7D%20%20%5C%5C%20%20%5Csqrt%5B4%5D%7B%20%5Cfrac%7B625%7D%7B16%7D%20%7D%20%20%3D%20%20%5Cfrac%7B%20%5Csqrt%5B4%5D%7B625%7D%20%7D%7B%20%5Csqrt%5B4%5D%7B16%7D%20%7D%20%20%20%5C%5C%20%20%5Cfrac%7B%20%5Csqrt%5B4%5D%7B%20%7B5%7D%5E%7B4%7D%20%7D%20%7D%7B%20%5Csqrt%5B4%5D%7B16%7D%20%7D%20%20%3D%20%20%5Cfrac%7B%20%5Csqrt%5B4%5D%7B%20%7B5%7D%5E%7B4%7D%20%7D%20%7D%7B%20%5Csqrt%5B4%5D%7B%20%7B2%7D%5E%7B4%7D%20%7D%20%7D%20%20%3D%20%20%5Cfrac%7B5%7D%7B2%7D%20)
When you add the equations in (a) you get 7x+y=24.
When you subtract the equations in (b) you also get 7x+y=24.
That means to solve both systems you can work with the same equation. However that is not enough. We must have two equivalent equations. We found only one.
Notice however that in the (b) we can take the first equation and divide every term by 2. When we do this we get 4x-5y=13. That’s the first equation in (a).
So both systems can be solved by working with the same two equations. These are 5x-5y=13 and 7x+y=24. And since we have two equations and two unknowns (the number of equations matches the number of variables) there is only one solution — one x and y that would make both systems true — solve both systems.
Basically we showed the systems are equivalent!
