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3 years ago

What!!!?!?! Could someone help me with the first two I don't understand and it's due tomorrow

Mathematics

1 answer:

Delicious77 [7]3 years ago

3 0

If said number is x, that means that twice (2 times) a number and 2x-7=13. Adding 7 to both sides, we get 2x=20 and by dividing both sides by 2 we get x=10. For 2, we see that the sum of a number and 6 is first priority, so we have (x+6)*7=-43. Dividing both sides by 7, we get x+6=-43/7. After that, we subtract both sides by 6 to get -43/7-6=x

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How many solutions can be found for the linear equation? 4(x + 5) - 5 = 8x + 18 2

Elena L [17]

Answer:

$4x + 20 - 5 = 0 \\ 4x + 15 = 0 \\ 4x = - 15 \\ x = - \frac{15}{4}$

Step-by-step explanation:

$8x + 18 = 0 \\ 8x = - 18 \\ x = - \frac{18}{8} \\ x = - \frac{9}{4}$

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3 years ago

Manuel has $600 in a savings account at the beginning of the summer. He wants to have at least $300 in the account at the end of

stiks02 [169]

The answer to this question is 600-28w > 300. This inequality can be described as $600 (money in the savings account) subtracted by $28w (withdrawal of $28 a week for food) should be greater than $300. It proves that the money will not drop below $300.

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3 years ago

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What is the measure of ZBAQ 1 B 84 0 x 140

Dahasolnce [82]

Answer:

117.600

Step-by-step explanation:

7 0

3 years ago

Prove that there exists a unique real number solution to the equation x3 + x2 − 1 = 0 between x = 2/3 and x=1

ziro4ka [17]

Replace each of the x values given to see if they give 0.

0=(2/3)³+(2/3)²-1
0=(8/27)+(4/9)-1
0≠-0.259

0=(1)³+(1)²-1
0≠1

Therefore, you can see that the solution would have to be between 2/3 and 1.

Hope I helped :)

7 0

3 years ago

ABCD is a parallelogram. Segment AC = 4x + 10. Find the value of x and y.

valkas [14]

Answer:

The values of x and y in the diagonals of the parallelogram are x=0 and y=5

Step-by-step explanation:

Given that ABCD is a parallelogram

And segment AC=4x+10

From the figure we have the diagonals AC=3x+y and BD=2x+y

By the property of parallelogram the diagonals are congruent

∴ we can equate the diagonals AC=BD

That is 3x+y=2x+y

3x+y-(2x+y)=2x+y-(2x+y)

3x+y-2x-y=2x+y-2x-y

x+0=0 ( by adding the like terms )

∴ x=0

Given that segment AC=4x+10

Substitute x=0 we have AC=4(0)+10

=0+10

=10

∴ AC=10

Now (3x+y)+(2x+y)=10

5x+2y=10

Substitute x=0, 5(0)+2y=10

2y=10

$y=\frac{10}{2}$

∴ y=5

∴ the values of x and y are x=0 and y=5

5 0

3 years ago