Add 11 + 16. Plug in 11 into b-2 since b equals eleven. You should now have 11+16+11-2. Do the same thing and plug in 16 for c and 11 for b for c-b. Your solution will now be 11+16+11-2+16-11.
Subtract the number she completed from what she had left to paint originally.
The fractions have different denominators so first step is to rewrite the fractions with a common denominator.
23/25 can be rewritten as 92/100
Now you have 78 21/100 - 34 92/100
Because 21/100 is smaller than 92/100 subtract 1 whole number from 78 and rewrite 1 as 100/100 and add that to the fraction.
78 21/100 becomes 77 121/100
Now subtract :
77 121/100 - 34 92/100
77-34 = 43
And 121/100 - 92/100 = 29/100
Combine to get 43 and 29/100
Answer: 288 students
Step-by-step explanation:
<u>First Step: find the number of students per bus</u>
Given
- 144 students
- 4 bus
Solve
144 students/4 buses=36 students/bus
<u />
<u>Second Step: apply the rate to find the number of students in 8 buses</u>
Given
- 8 buses
- 36 students/bus
Solve
8×36=288 students
Hope this helps!! :)
Please let me know if you have any questions
Answer: 325
Step-by-step explanation:
Student tickets: x
Adult tickets: x + 71
Total: 579
x + x + 71 = 579
2x + 71 = 579
2x = 579 - 71
2x = 508
x = 508/2
x = 254
Adult tickets = x + 71 = 254 + 71 = 325
P.S. Hope it helps. If you have any questions, feel free to ask them here. I'll be happy to help! Have a wonderful day!
The minimum value of a function is the place where the graph has a vertex at its lowest point.
There are two methods for determining the minimum value of a quadratic equation. Each of them can be useful in determining the minimum.
(1) By plotting graph
We can find the minimum value visually by graphing the equation and finding the minimum point on the graph. The y-value of the vertex of the graph will be the minimum.
(2) By solving equation
The second way to find the minimum value comes when we have the equation y = ax² + bx + c.
If our equation is in the form y = ax^2 + bx + c, you can find the minimum by using the equation min = c - b²/4a.
The first step is to determine whether your equation gives a maximum or minimum. This can be done by looking at the x² term.
If this term is positive, the vertex point will be a minimum; if it is negative, the vertex will be a maximum.
After determining that we actually will have a minimum point, use the equation to find it.
