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igor_vitrenko [27]
3 years ago
13

Find the total number of unit cube that fill the entire prism

Mathematics
1 answer:
Nonamiya [84]3 years ago
3 0

Answer:

72 cubes

Step-by-step explanation:

Attached is the picture drawn (though not great one), showing 6 cube on length of prism, 3 cubes on width and 4 cubes on height of prism.

Given: Length of prism= 6

           Width= 3

            Height= 4

To know the number of cubes, which can fill the entire prism, we need to find volume of prism.

∴ Volume of prism= length\times width\times height

Volume of prism= 6\times 3\times 4= 72

∴ 72 units of cube can fill the entire prism.

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You didn’t add a picture, so it’s impossible to answer
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3 years ago
Find the exact solution to the equation 10-log8(x+2)=9
ohaa [14]

Answer:

-0.89269063 ...

Step-by-step explanation:

Put it in the calculator

8 0
3 years ago
The diameter of a particle of contamination (in micrometers) is modeled with the probability density function f(x)= 2/x^3 for x
natulia [17]

Answer:

a) 0.96

b) 0.016

c) 0.018

d) 0.982

e) x = 2

Step-by-step explanation:

We are given with the Probability density function f(x)= 2/x^3 where x > 1.

<em>Firstly we will calculate the general probability that of P(a < X < b) </em>

       P(a < X < b) =  \int_{a}^{b} \frac{2}{x^{3}} dx = 2\int_{a}^{b} x^{-3} dx

                            = 2[ \frac{x^{-3+1} }{-3+1}]^{b}_a   dx    { Because \int_{a}^{b} x^{n} dx = [ \frac{x^{n+1} }{n+1}]^{b}_a }

                            = 2[ \frac{x^{-2} }{-2}]^{b}_a = \frac{2}{-2} [ x^{-2} ]^{b}_a

                            = -1 [ b^{-2} - a^{-2}  ] = \frac{1}{a^{2} } - \frac{1}{b^{2} }

a) Now P(X < 5) = P(1 < X < 5)  {because x > 1 }

     Comparing with general probability we get,

     P(1 < X < 5) = \frac{1}{1^{2} } - \frac{1}{5^{2} } = 1 - \frac{1}{25} = 0.96 .

b) P(X > 8) = P(8 < X < ∞) = 1/8^{2} - 1/∞ = 1/64 - 0 = 0.016

c) P(6 < X < 10) = \frac{1}{6^{2} } - \frac{1}{10^{2} } = \frac{1}{36} - \frac{1}{100 } = 0.018 .

d) P(x < 6 or X > 10) = P(1 < X < 6) + P(10 < X < ∞)

                                = (\frac{1}{1^{2} } - \frac{1}{6^{2} }) + (1/10^{2} - 1/∞) = 1 - 1/36 + 1/100 + 0 = 0.982

e) We have to find x such that P(X < x) = 0.75 ;

               ⇒  P(1 < X < x) = 0.75

               ⇒  \frac{1}{1^{2} } - \frac{1}{x^{2} } = 0.75

               ⇒  \frac{1} {x^{2} } = 1 - 0.75 = 0.25

               ⇒  x^{2} = \frac{1}{0.25}   ⇒ x^{2} = 4 ⇒ x = 2  

Therefore, value of x such that P(X < x) = 0.75 is 2.

8 0
3 years ago
Collin did the work to see if 10 is a solution to the equation r/4=2.5
Natasha2012 [34]

Answer:

Yes, because if you substitute 10 for r in the equation and simplify, you find that the equation is true.

Step-by-step explanation:

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3 0
3 years ago
Subtract: (x^2 - 8x + 5)-(-3x^2 + 5x-9)
Marianna [84]

Answer: 4x^2 -13x + 14

Step-by-step explanation:

(x^2 - 8x + 5)-(-3x^2 + 5x-9)

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(4x^2 - 8x + 5)-(5x-9)

Subtract 5x from -8x

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Subtract 9 from 5

4x^2 -13x + 14

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