Question

Solve the given triangle by finding the missing angle and other side lengths.

Answer 1

Answer:

∠ABC= 180° -21° -37° (∠ sum of triangle ABC)

∠ABC= 122°

Using sine rule,

$\frac{AB}{sin21°} = \frac{200}{sin122°}$

AB= 200(sin21°)/sin 122°

AB= 84.5 units (3 s.f.)

$\frac{BC}{sin37°} = \frac{200}{sin122°}$

BC= 200(sin37°)/ sin122°

BC= 142 units (3 s.f.)