Answer:
"number line with open circles on negative 9 and 5, shading going in the opposite directions."
Step-by-step explanation:
Your inequality doesn't include an equal sign so there will be no closed holes. It will only be open holes.
|u|>14 means that the number u has to be greater than 14 or less than -14. These numbers I describe just now all have a distance greater than 14 from 0.
So |u|>14 implies u>14 or u<-14.
But we are solving |2x+4|>14 so this implies we have 2x+4>14 or 2x+4<-14.
2x+4>14
Subtract 4 on both sides:
2x >10
Divide both sides by 2:
x >5
2x+4<-14
Subtract 4 on both sides:
2x <-18
Divide both sides by 2:
x <-9
So our solution is x>5 or x<-9.
Graphing!
~~~~~~~O O~~~~~~~~
-----------(-9)---------------------------------(5)---------------
So we shaded to the right of 5 because our inequality says x is bigger than 5.
We shaded to the left of -9 because our inequality says x is less than -9.
Answer:
64.6 km/h
Step-by-step explanation:
18:14 = 18h 14'
1h = 60'
18h = 17h + 60'
18h14' = 17h + 60' ´14' = 17h 74'
then:
17h 74'
-17h 22'
= 0h 52'
the train travelled 56km at 52 minutes
56km/52minutes
1 hour = 60 minutes
52 minutes = 52/60 = 0.86667 hours
then:
56km/52minutes = 56km/0.86667hours
= 64.615 km/hours
Answer:
6
Step-by-step explanation:
Answer:
f'(9) = 6
Step-by-step explanation:
f(x) = 6x+7
The derivative is
f'(x) = 6
Evaluated at x=9
f'(9) = 6
The area formula of a circle is 
× π.
With that being said, we can solve both problems!
Starting with part A:
-The radius we know is 21cm. From there, we can substitute in our formula with the new value.
x π
From there, we can square our radius:
(21 x 21) x π
(441) x π
And finally, we can multiply by pi to get our answer.
(441) x π
1385.44236023
Which rounded to the nearest tenth is 1385.4. Therefore, the area of the porthole is 1385.4 centimetres.
The second part can be followed with the same process, hopefully you understand the concept enough to where you're comfortable solving problems like this on your own. Feel free to reach out if you have any further trouble!
<em>Hope this helped! :)</em>
