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shutvik [7]
3 years ago
5

Which statements are true?

Mathematics
1 answer:
Nata [24]3 years ago
5 0

Answer:

123

Step-by-step explanation:

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Write 8.12 as a mixed number in simplest form.<br> (It’s a repeating decimals
kicyunya [14]

Answer:

8 3/25 because 8.12 is 8 12/100 and when you simplify 12/100 you get 3/25

8 0
3 years ago
Linear Relationships Study Guide 1.) Select all the equations for which (-6, -1) is a solution. Show your work to prove that eac
TiliK225 [7]

we have point (-6, - 1)

Now we will put these points in each equation,

y = 4x +23

put x = -6 and y = -1

-1 = 4 (-6) +23

-1 = -24 + 23

-1 = -1

LHS = RHS, so this equation has (-6 , -1) as solution.

y = 6x

put x = -6 and y = -1

-1 = 6 (-6)

-1 not= -36

LHS is not equal RHS, so (-6 , -1) is not a solution for that equation,

y = 3x - 5

put x = -6 and y = -1

-1 = 3 (-6) - 5

-1 = -18 - 5

-1 not= -23

LHS is not equal RHS, so (-6 , -1) is not a solution for that equation,

y= 1/6 x

put x = -6 and y = -1

-1 = -6/6

-1 = -1

LHS = RHS, so (-6 , -1) is a solution for that equation,

6 0
1 year ago
What is the scale factor of the following dilation DO,K (9,6) → (3, 2)
Mars2501 [29]

(9,6)

-------- = (3,2)

3

This means that the dilation of (9, 6) to (3, 2) is (1/3(x), 1/3(y))

⭐ Answered by Hyperrspace (Ace) ⭐

⭐ Brainliest would be appreciated, I'm trying to reach genius! ⭐

⭐ If you have questions, leave a comment, I'm happy to help! ⭐

4 0
3 years ago
How to solve this problem im not getting a good answer
kow [346]
Well, you have to simplify the bottom part to be able to answer it as a whole number. Hope this helps. 
7 0
3 years ago
Read 2 more answers
You deposit $5000 in an account earning 8% interest compounded monthly. How much will you have in the account in 15 years?
Rasek [7]

\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$5000\\ r=rate\to 8\%\to \frac{8}{100}\dotfill &0.08\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{monthly, thus twelve} \end{array}\dotfill &12\\ t=years\dotfill &15 \end{cases}

\bf A=5000\left(1+\frac{0.08}{12}\right)^{12\cdot 15}\implies A=5000(1.00\overline{66})^{180}\implies A\approx 16534.61

5 0
3 years ago
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