remember, x is on the left side for x- intercept while Y is on the right but you put it on the left for the Y intercept.
example
x intercept is (-5, 0, 5)
This is a system of equations problem. Set up the 2 equations like so: If the angles are complementary then they add up to 90, therefore, a + b = 90. We also know that a is 16 more than b. The word "is" means equals and "more" is addition. Therefore, a is 16 more than b is "a = b + 16". Now sub in that value of a (b + 16) into the first equation and solve for b. Then back-substitute to solve for a. (b + 16) + b = 90 so 2b + 16 = 90 and 2b = 74. So b = 37. If b = 37, then a + 37 = 90 and a = 53. Check yourself to make sure that 37 + 53 add up to equal 90 (they do, just get used to checking yourself for accuracy).
No, it is one hundred times greater than the first 4.
Please look up and apply Heron's Formula. Start by calculating s, where
a + b + c
s = -------------------
2
Then calculate A:
A = sqrt[ s(s-a)(s-b)(s-c) ]
Answer:
Step-by-step explanation:
![3\log_5(x-10)-\dfrac{1}{2}\log_54=5\log_52\\\\\text{Domain:}\ x-10>0\to x>10\\\\\text{use}\\\\\log_ab^n=n\log_ab\\\\\log_ab-\log_ac=\log_a\left(\dfrac{b}{c}\right)\\========================\\\\\log_5(x-10)^3-\log_54^\frac{1}{2}=\log_52^5\qquad\text{use}\ a^\frac{1}{2}=\sqrt{a}\\\\\log_5(x-10)^3-\log_5\sqrt4=\log_532\\\\\log_5(x-10)^3-\log_52=\log_532\\\\\log_5\dfrac{(x-10)^3}{2}=\log_532\iff\dfrac{(x-10)^3}{2}=32\qquad\text{multiply both sides by 2}\\\\(x-10)^3=64\to x-10=\sqrt[3]{64}\\\\x-10=4\qquad\text{add 10 to both sides}\\\\x=14\in D](https://tex.z-dn.net/?f=3%5Clog_5%28x-10%29-%5Cdfrac%7B1%7D%7B2%7D%5Clog_54%3D5%5Clog_52%5C%5C%5C%5C%5Ctext%7BDomain%3A%7D%5C%20x-10%3E0%5Cto%20x%3E10%5C%5C%5C%5C%5Ctext%7Buse%7D%5C%5C%5C%5C%5Clog_ab%5En%3Dn%5Clog_ab%5C%5C%5C%5C%5Clog_ab-%5Clog_ac%3D%5Clog_a%5Cleft%28%5Cdfrac%7Bb%7D%7Bc%7D%5Cright%29%5C%5C%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%5C%5C%5C%5C%5Clog_5%28x-10%29%5E3-%5Clog_54%5E%5Cfrac%7B1%7D%7B2%7D%3D%5Clog_52%5E5%5Cqquad%5Ctext%7Buse%7D%5C%20a%5E%5Cfrac%7B1%7D%7B2%7D%3D%5Csqrt%7Ba%7D%5C%5C%5C%5C%5Clog_5%28x-10%29%5E3-%5Clog_5%5Csqrt4%3D%5Clog_532%5C%5C%5C%5C%5Clog_5%28x-10%29%5E3-%5Clog_52%3D%5Clog_532%5C%5C%5C%5C%5Clog_5%5Cdfrac%7B%28x-10%29%5E3%7D%7B2%7D%3D%5Clog_532%5Ciff%5Cdfrac%7B%28x-10%29%5E3%7D%7B2%7D%3D32%5Cqquad%5Ctext%7Bmultiply%20both%20sides%20by%202%7D%5C%5C%5C%5C%28x-10%29%5E3%3D64%5Cto%20x-10%3D%5Csqrt%5B3%5D%7B64%7D%5C%5C%5C%5Cx-10%3D4%5Cqquad%5Ctext%7Badd%2010%20to%20both%20sides%7D%5C%5C%5C%5Cx%3D14%5Cin%20D)
