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ArbitrLikvidat [17]
3 years ago
12

Pls help 10 points plsssssss help

Mathematics
2 answers:
vovangra [49]3 years ago
8 0

Answer:

9

Step-by-step explanation:

I looked it up

trapecia [35]3 years ago
7 0

Answer:

9

Step-by-step explanation: It is 9 because if you take 15 and drag the decimal point to the right two times(.15). Then you multiply .15 x 60 it will end up becoming 9.

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Is the Square root of 127 rational or irrational
labwork [276]

Irrational, because there is no number multiplied by itself that will have an answer of 127


4 0
3 years ago
Read 2 more answers
Help needed asap graph posted below
Aloiza [94]
Answer: D) (x+1)(x + 2)(x-3)

This is because the roots are x = -1, x = -2 and x = 3
Simply get all the numbers to each side to have 0 on the right side

x = -1 turns into x+1 = 0
x = -2 turns into x+2 = 0
x = 3 turns into x-3 = 0

The three factors are (x+1), (x+2) and (x-3)
Which leads to (x+1)(x+2)(x-3)

6 0
3 years ago
Simplify completely. <br><br> <img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B68%7D%20" id="TexFormula1" title=" \sqrt{68} " alt=
Keith_Richards [23]
\bf \sqrt{68}\qquad &#10;\begin{cases}&#10;68=2\cdot 2\cdot 17\\&#10;\qquad 2^2\cdot 17&#10;\end{cases}\qquad \sqrt{2^2\cdot 17}\implies 2\sqrt{17}
3 0
3 years ago
Determine whether each pair of segments is congruent
Dafna1 [17]

They are both labeled as 3 feet, so both must be equal, unless you doubt the labeling. Unless that is so, then both segments are equal.

6 0
4 years ago
the second term in a geometric sequence is 12. the fourth term in the same sequencce is 4/3. what is the common ratio in this se
nordsb [41]
Geo is
an=a1r^(n-1)

2nd term is 12
4th term is 4/3

a2=a1r^(2-1)=12
a2=a1r=12

a4=a1r^(4-1)=4/3
a4=a1r^3=4/3

we have
a1r=12 and a1r^3=4/3
(a1r^3)/(a1r)=r^2=(4/3)/12=1/9

1/9=r^2
sqrt oth sides
1/3=r

the common ratio is 1/3
5 0
4 years ago
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