5. m∠C = 95°
6. m∠C = 70°
7. The other acute angle in the right triangle = 70°
8. m∠C = 70°
9. m∠C = 60° [equilateral triangle]
10. Measure of the exterior angle at ∠C = 110°
11. m∠B = 70°
12. m∠Z = 70°
<h3>What are Triangles?</h3>
A triangle is a 3-sided polygon with three sides and three angles. The sum of all its interior angles is 180 degrees. Some special triangles are:
- Isosceles triangle: has 2 equal base angles.
- Equilateral triangle: has three equal angles, each measuring 60 degrees.
- Right Triangle: Has one of its angles as 90 degrees, while the other two are acute angles.
5. m∠C = 180 - 50 - 35 [triangle sum theorem]
m∠C = 95°
6. m∠C = 180 - 25 - 85 [triangle sum theorem]
m∠C = 70°
7. The other acute angle in the right triangle = 180 - 90 - 25 [triangle sum theorem]
The other acute angle = 70°
8. m∠C = 180 - 55 - 55 [isosceles triangle]
m∠C = 70°
9. m∠C = 60° [equilateral triangle]
10. Measure of the exterior angle at ∠C = 50 + 60
Measure of the exterior angle at ∠C = 110°
11. m∠B = 115 - 45
m∠B = 70°
12. m∠Z = 180 - 35 - 75
m∠Z = 70°
Learn more about triangles on:
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Solution:
A coin is flipped three times,resulting three heads in a row.
Since Steve has mentioned that , each flip of a coin is unconnected to the previous flip.
Two or more events are said to be independent if occurrence of one of them is not affected by the Occurrence of other.
This is an example of independent events.
In terms of probability, P (A∩B∩C)= P(A)×P(B)×P(C)
Sent a picture of the solution to the problem (s).
Since there is a negative correlation, evident by the negative slope of the equation of the line given to be -0.5, if we take t as 0, we get an equation of,
s = 3.6
This means that if a student does not watch television, he or she spends a maximum of 3.6 hours studying.
is in quadrant I, so
.
is in quadrant II, so
.
Recall that for any angle
,

Then with the conditions determined above, we get

and

Now recall the compound angle formulas:




as well as the definition of tangent:

Then
1. 
2. 
3. 
4. 
5. 
6. 
7. A bit more work required here. Recall the half-angle identities:



Because
is in quadrant II, we know that
is in quadrant I. Specifically, we know
, so
. In this quadrant, we have
, so

8. 