I have no idea how to help you srry . . . . .
Answer:
Step-by-step explanation:
We are given a circle with a partially shaded region. First, we need to determine the area of the whole circle. To do this, we need the measurement of the radius of the circle:
Use the Pythagorean theorem to solve for the other leg of the right triangle inside the circle:
5^2 = 3^2 + x^2
x = 4
The radius is 4 + 1 cm = 5 cm
So the area of the circle is A = pi*r^2
A = 3.14 * (5)^2
A = 25pi cm^2
To solve for the area of the shaded region:
Ashaded = Acircle - Atriangles
we need to solve for the area of the triangles:
A = 1/2 *b*h
A = 1/2 *6 * 5
A = 15 cm^2
Atriangles = 2 * 15
Atriangles = 30 cm^2
Ashaded = 25pi - 30
A 12-sided die is rolled. The set of equally likely outcomes is {1,2,3,4,5,6,7,8,9,10,11,12}. Find the probability of rolling
UNO [17]
1/6 is the probability of rolling a dice and getting less than 3.
0.0167
Since the decimal is present, start from the left side of the number and move to the right until you hit the first Non-Zero number. That number will be the first significant figure, and the number you will start counting from. That’s the first, the second is next, and lastly the third. You round the LAST significant figure, in this case a 6 followed by a 6, meaning you round UP.
Write the 2 equations:
5x-2y=18
-5x+3y=-22
You can see that the coefficients of x are opposites, so you can add them(the 2 equations) to eliminate x.
Adding them, you get:
y=-3
So now that you know y, you can substitute the value of y into one of the original equations. Let's substitute it in the first one:
5x+6=18
Solving this, we get:
5x=12
x=12/5
x=12/5, y=-3
