$\dfrac{3}{y-2}-2=\dfrac{1}{y-1}\\\\\\\text{Multiply by the LCD (y-2)(y-1) to clear the denominator:}\\\\\dfrac{3}{y-2}(y-2)(y-1)-2(y-2)(y-1)=\dfrac{1}{y-1}(y-2)(y-1)\\\\\\3(y-1)-2(y-2)(y-1)=1(y-2)\\\\3y-3-2(y^2-3y+2)=y-2\\\\3y-3-2y^2+6y-4=y-2\\\\-2y^2+9y-7=y-2\\\\0=2y^2-8y+5\quad \rightarrow \quad a=2,\ b=-8,\ c=5\\\\\\\text{Quadratic formula is: }x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\\x=\dfrac{-(-8)\pm \sqrt{(-8)^2-4(2)(5)}}{2(2)}\\\\\\.\ =\dfrac{8\pm \sqrt{64-40}}{2(2)}$

$.\ =\dfrac{8\pm \sqrt{24}}{2(2)}\\\\\\.\ =\dfrac{8\pm 2\sqrt{6}}{2(2)}\\\\\\.\ =\dfrac{4\pm \sqrt{6}}{2}$

7 0

3 years ago

A garden supply store sells two types of lawn mowers. The smaller mower costs $249.99 and the larger mower costs $329.99. 30 tot

lys-0071 [83]

Answer:

15( b+ a) - 2(a + 0 ) = c

then

c+b = t

We could put the two together to make 15(b+a)- 2(a+0) + b = t

Where t = 8379.70

a= £249.99 b= 329.99

Step-by-step explanation:

Equal amounts are 8549.7 from 30 mowers a+b = small and large.

If we use this as an even and take away a+b at different equations we can find the answer to be 8379.70 on the 2nd equation. First equation = 8579.70

8549.7- 249.99-249.99+329.99 to equal the given year to find c in first equation and total in year = t within the above equation.

6 0

3 years ago

Please please please help help help help help!!!!!!!!!!!!!

Feliz [49]

Answer:

15 and 108

Step-by-step explanation:

3*(30-25)=3*5=15

4*(12+15)=4*27=108

5 0

3 years ago