All categories

3 years ago

What is a number t divided by 82 in an algebraic expression?

2 answers:

3 0

Hey there, Lets solve this step by step.

A number t divided by 82

Let the number be represented by y.

t divided by 82 = t / 8

Therefore-

$y= t/82$

In algebraic expressions, "y" is normally used as the dependent variable and "x" is normally used as the independent variable, instead of other variables. So that is why i used the variable y in the equation.

Paul [167]3 years ago

3 0

Answer:

a number t divided by 82 is $\frac{t}{82}$

Step-by-step explanation:

a number t divided by 82

An algebraic expression contains variables and operators like +,- x or /

A variable can be an alphabet . for example a, b, c

a number t divided by 82

HEre 't' is a variable

t is divided by 82, so here we use division symbol

$\frac{t}{82}$

You might be interested in

If the table represents a linear function, what's the missing value of y?

Svetach [21]

C) 13

The y value adds one by every x; therefore 4 would be 13.

3 0

3 years ago

What is 3/8+1/3? They are fractions

victus00 [196]

Answer:

Result in decimals: 0.70833333333333

Calculation steps:

3 × 3

8 × 3

1 × 8

3 × 8

9 + 8

5 0

3 years ago

Read 2 more answers

Rachna borrowed a certain sum at the rate of 15% per annum. if she paid at the end of the two years Rs.1290 as interest Compound

Natalija [7]

Given info:

Compound Interest = Rs.1290

Rate of Interest = 15% p.a

Time = 2 years

<h3>Formula we have to know:-</h3>

$\dag{\underline{\boxed{\sf{C.I = P \bigg(1 + \dfrac{R}{100} \bigg)^{n} - 1}}}}$

Where

C.I = Compound Interest

P = Principle

R = Rate of Interest

N = Time

$\textsf{ \underline{Solution-}}\\$

Here

C.I = Rs.1290

R = 15%

N = 2 years

Principle = ?

Now,Calculating the sum (Principle) borrowed by Rachna

$\quad{: \implies{\sf{C.I = \Bigg[P \bigg(1 + \dfrac{R}{100} \bigg)^{n} - 1 \Bigg]}}}$

Substituting the given values

$\quad{: \implies{\sf{1290 = \Bigg[P \bigg(1 + \dfrac{15}{100} \bigg)^{2} - 1 \Bigg]}}}$

$\quad{: \implies{\sf{1290 = \Bigg[P \bigg(\dfrac{(1 \times 100) + 15}{100} \bigg)^{2} - 1 \Bigg]}}}$

$\quad{: \implies{\sf{1290 = \Bigg[P \bigg(\dfrac{115}{100} \bigg)^{2} - 1 \Bigg]}}}$

$\quad{: \implies{\sf{1290 = \Bigg[P \bigg(\dfrac{115}{100} \times \dfrac{115}{100} \bigg) - 1 \Bigg]}}}$

$\quad{: \implies{\sf{1290 = \Bigg[P \bigg(\dfrac{13225}{10000} \bigg) - 1 \Bigg]}}}$

$\quad{: \implies{\sf{1290 = \Bigg[P \bigg( \cancel{\dfrac{13225}{10000}} \bigg) - 1 \Bigg]}}}$

$\quad{: \implies{\sf{1290 = \Bigg[P \bigg({1.3225 - 1} \bigg) \Bigg]}}}$

$\quad{: \implies{\sf{1290 = P \times {0.3225}}}}$

$\quad{: \implies{\sf{\dfrac{1290}{0.3225} = P}}}$

$\quad{: \implies{\sf{\dfrac{1290 \times 1000}{0.3225 \times 1000} = P}}}$

$\quad{: \implies{\sf{\dfrac{12900000}{3225} = P}}}$

$\quad{: \implies{\sf{\cancel{\dfrac{12900000}{3225}} = P}}}$

$\quad{: \implies{\sf{Rs.4000 = P}}}$

$\quad{\dag{\underline{\boxed{\tt{\blue{Principle} = \purple{Rs.4000 }}}}}}$

$\begin{gathered}\end{gathered}$

Hence,

The sum (Principle) is Rs.4000.

3 0

3 years ago

Write the equation in slope intercept form. Then find the slope and y intercept of the line. Y=-5

lisov135 [29]

$\bf y=\stackrel{slope}{m}x+\stackrel{y-intercept}{b}
\\\\\\
y=-5\implies y=0x-5\implies y=\stackrel{slope}{0}x\stackrel{y-intercept}{-5}$

3 0

4 years ago

What is: d (100,000)=1/10x+500

Sergio039 [100]

X is 995,000

d is 100,000 respectfully

4 0

4 years ago