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Rashid [163]
3 years ago
14

Can someone help me with this assignment. It would also be really helpful if you could show me how to work out the problems.

Mathematics
1 answer:
BabaBlast [244]3 years ago
5 0
When adding or subtracting fractions, multiply to get the same denominator (bottom number).

\frac{4}{5}*( \frac{4}{4})  -   \frac{1}{4} * (\frac{5}{5} ) =  \frac{16}{20} -   \frac{5}{20} =  \frac{11}{20}

When multipling two fractions, just multiply straight across, factor diagonally if possible.

\frac{7}{13} * \frac{5}{6} =  \frac{35}{78}

When dividing fractions, flip the second fraction over and multiply.

\frac{13}{17} /  \frac{3}{2} =  \frac{13}{17} *  \frac{2}{3} =  \frac{26}{51}

For the polynomials, you just need to combine like terms.

3x +  4y² + 7x + 6y² = (3x + 7x) + (4y² + 6y²) = 10x + 10y²

You can factor this further but I don't know if its necessary.

= 10(x + y)

Let me know if you have any questions.

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<h2>x = 1, y = 3 → (1, 3)</h2>

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\left\{\begin{array}{ccc}-2x+y=1\\-4x+y=-1&\text{change the signs}\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}-2x+y=1\\4x-y=1\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad2x=2\qquad\text{divide both sides by 2}\\.\qquad x=1\\\\\text{Put it to the first equation:}\\\\-2(1)+y=1\\-2+y=1\qquad\text{add 2 to both sides}\\y=3

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Step-by-step explanation:

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7/9

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