Answer:
Correct option: third one -> 12
Step-by-step explanation:
In a polygon with 'n' vertex, we can trace diagonals from one vertex to all vertices, except to the vertex chosen and the two adjacent vertices (because we would have sides and not diagonals), so we would have 'n - 3' diagonals.
If we have a polygon with 15 vertex, the number of diagonals from one vertex is 15 - 3 = 12.
Correct option: third one
Answer:
I think you need to mutply those. And you will get your answer.
Step-by-step explanation:
<span>So, L*W=A Because it is 4 cm longer, L=W+4 Because the area is 96, LW=96 Substitute to get W(W+4)=96 Multiply it out. W^2+4W-96=0 By solving the quadratic, W+12(W-8)=0 so either W+12 or W-8 is zero. The width must be positive, so the width is 8. Therefore the length is 12.
Hope this helps.</span>
Answer:

Step-by-step explanation:
so you already have the formula, which is
![\sqrt[3]{ \frac{3v}{4\pi} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B3v%7D%7B4%5Cpi%7D%20%7D%20)
the v represents Volume.
and 3v would be 3×volume.
![\sqrt[3]{ \frac{3 \times 1000}{4 \times \pi} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B3%20%5Ctimes%201000%7D%7B4%20%5Ctimes%20%5Cpi%7D%20%7D%20)
![\sqrt[3]{ \frac{3000}{12.56637061} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B3000%7D%7B12.56637061%7D%20%7D%20)
![\sqrt[3]{238.7324147 }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B238.7324147%20%7D%20)

to the nearest tenth place.
