I'm guessing that you want to find the segment area of a circle that has a radius AO = 8" and a chord AB with a length of 8".
Sine angle AOD = AE / OA
Sine angle AOD = 4 / 8
Sine angle AOD = .5
arc sine (.5) = 30 degrees
So, angle AOB = 60 degrees
Circle Area = PI * radius^2
Circle Area =
<span>
<span>
<span>
201.06</span></span></span>
Sector Area = (60/360) * 201.06
Sector Area = 33.51
Line OE^2 = AO^2 -AE^2
Line OE^2 = 64 -16
Line OE =
<span>
<span>
<span>
6.9282032303
</span>
</span>
</span>
Triangle AOB Area = OE*AE = <span>
<span>
<span>
6.9282032303 * 4
</span></span></span>Triangle AOB Area =
<span>
<span>
<span>
27.7128129211
</span>
</span>
</span>
Segment Area = Sector Area -Triangle AOB Area
Segment Area = 33.51 -<span>27.71
</span>Segment Area = 5.80
Answer:
29.01
Step-by-step explanation:
5.10^2+3
(5.1*5.1)+3
26.01+3
<u><em>29.01</em></u>
Answer:
5.39
Step-by-step explanation:
if you are trying to find MN then it means you need to find the length.
we cant use slope, but we CAN make it a triangle!
*see the attached image*
we can use A^2+B^2 to get what the hypotenuse is or C^2 is
2^2+5^2
4+25=29
the square root of 29 is 5.385
then we just round to the hundreth!
5.39
(8>5, so we bump him up)
hope this helped!
Answer:
About 432 people read at least one book per month.
Step-by-step explanation:
36/50 people read at least one book, multiply 36/50 by 12 to make the fraction 432/600.