4 (b-6)+19 simplify the expression

Daniel goes out to lunch. The bill, before tax and tip, was $14.20. A sales tax of 8% was added on. Daniel tipped 24% on the amo

seraphim [82]

Answer: $19.02

Step-by-step explanation:

First find the sales tax paid. It will be paid on the cost of the meal:

= 14.20 * 8%

= $1.14

Then find the tip which was done after the sales tax was added:

= 24% * (14.20 + 1.14)

= 24% * 15.34

= $3.68

The total cost is:

= Gross amount + Sales tax + tip

= 14.20 + 1.14 + 3.68

= $19.02

3 0

3 years ago

Value of P: 3/15(p+10)=-15

ArbitrLikvidat [17]

Step 1 : 1 Simplify — 5 Equation at the end of step 1 : 1 (— • (p + 10)) - -15 = 0 5 Step 2 :Equation at the end of step 2 : (p + 10) ———————— - -15 = 0 5 Step 3 :Rewriting the whole as an Equivalent Fraction :

3.1 Subtracting a whole from a fraction

Rewrite the whole as a fraction using 5 as the denominator :

-15 -15 • 5 -15 = ——— = ——————— 1 5

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

3.2 Adding up the two equivalent fractions
Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

(p+10) - (-15 • 5) p + 85 —————————————————— = —————— 5 5 Equation at the end of step 3 : p + 85 —————— = 0 5 Step 4 :When a fraction equals zero : 4.1 When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

p+85 ———— • 5 = 0 • 5 5

Now, on the left hand side, the 5 cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :
p+85 = 0

Solving a Single Variable Equation :

4.2 Solve : p+85 = 0

Subtract 85 from both sides of the equation :
 p = -85

One solution was found : p = -85

7 0

3 years ago

-4 1/2x - 3/7= 1/4 find x

DiKsa [7]

- 4(1/2)x - (3/7) = (1/4)
- 4(1/2)x = (1/4) + (3/7)
- (9/2)x = (7+12)/28
-(9/2)x = 19/28
x = (19/28) * 2 / 9
x = (19/14) / 9
x = 19 / (14*9)
x = 19 / 126

7 0

3 years ago

I wish to have $10,000 at the end of 8 years in a bank offering a simple interest rate of 7.5% per year. How much should I depos

cluponka [151]

Answer:

$6250

Step-by-step explanation:

6250x.075x8=3750

6250+3750=10,000

7 0

2 years ago

Evaluate the following limit:

Makovka662 [10]

If we evaluate the function at infinity, we can immediately see that:

$\large\displaystyle\text{$\begin{gathered}\sf \bf{\displaystyle L = \lim_{x \to \infty}{\frac{(x^2 + 1)^2 - 3x^2 + 3}{x^3 - 5}} = \frac{\infty}{\infty}} \end{gathered}$}$

Therefore, we must perform an algebraic manipulation in order to get rid of the indeterminacy.

We can solve this limit in two ways.

By comparison of infinities:

We first expand the binomial squared, so we get

$\large\displaystyle\text{$\begin{gathered}\sf \displaystyle L = \lim_{x \to \infty}{\frac{x^4 - x^2 + 4}{x^3 - 5}} = \infty \end{gathered}$}$

Note that in the numerator we get x⁴ while in the denominator we get x³ as the highest degree terms. Therefore, the degree of the numerator is greater and the limit will be \infty. Recall that when the degree of the numerator is greater, then the limit is \infty if the terms of greater degree have the same sign.

Dividing numerator and denominator by the term of highest degree:

$\large\displaystyle\text{$\begin{gathered}\sf L = \lim_{x \to \infty}\frac{x^{4}-x^{2} +4 }{x^{3}-5 } \end{gathered}$}\\$

$\ \ = \lim_{x \to \infty\frac{\frac{x^{4} }{x^{4} }-\frac{x^{2} }{x^{4}}+\frac{4}{x^{4} } }{\frac{x^{3} }{x^{4}}-\frac{5}{x^{4}} } }$

$\large\displaystyle\text{$\begin{gathered}\sf \bf{=\lim_{x \to \infty}\frac{1-\frac{1}{x^{2} } +\frac{4}{x^{4} } }{\frac{1}{x}-\frac{5}{x^{4} } } \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =\frac{1}{0}=\infty } \end{gathered}$}$

Note that, in general, 1/0 is an indeterminate form. However, we are computing a limit when x →∞, and both the numerator and denominator are positive as x grows, so we can conclude that the limit will be ∞.

5 0

1 year ago