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Leokris [45]
3 years ago
15

Kira needs to memorize words on a vocabulary list for Latin class. She has words to memorize, and she is five-sixths done. How m

any words has Kira memorized so far?
Mathematics
1 answer:
SOVA2 [1]3 years ago
7 0

what is the total number of words?


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Determine is an outlier is present in the given data set: 43, 69, 78, 88, 54, 73, <br> 54, 59,70
kodGreya [7K]

Answer:

43

Step-by-step explanation:

43 is the most the lowest number while the others are around the same range

Hope this helps! Pls mark brainliest!

6 0
3 years ago
Suppose x is a real number and epsilon &gt; 0. Prove that (x - epsilon, x epsilon) is a neighborhood of each of its members; in
kaheart [24]

Answer:

See proof below

Step-by-step explanation:

We will use properties of inequalities during the proof.

Let y\in (x-\epsilon,x+\epsilon). then we have that x-\epsilon. Hence, it makes sense to define the positive number delta as \delta=\min\{x+\epsilon-y,y-(x-\epsilon)\} (the inequality guarantees that these numbers are positive).

Intuitively, delta is the shortest distance from y to the endpoints of the interval. Now, we claim that (y-\delta,y+\delta)\subseteq  (x-\epsilon,x+\epsilon), and if we prove this, we are done. To prove it, let z\in (y-\delta,y+\delta), then y-\delta. First, \delta \leq y-(x-\epsilon) then -\delta \geq -y+x-\epsilon hence z>y-\delta \geq x-\epsilon

On the other hand, \delta \leq x+\epsilon-y then z hence z. Combining the inequalities, we have that  x-\epsilon, therefore (y-\delta,y+\delta)\subseteq  (x-\epsilon,x+\epsilon) as required.  

3 0
3 years ago
A runner ran of a 5 kilometer race in 21 minutes. They ran the entire race at a constant speed.
IgorLugansk [536]

Answer:

4.2

Step-by-step explanation:

the kilometro is 5 and race is 21. 5÷21=4.2

6 0
2 years ago
In the triangle pictured, let A, B, C be the angles at the three vertices, and let a,b,c be the sides opposite those angles. Acc
Troyanec [42]

Answer:

Step-by-step explanation:

(a)

Consider the following:

A=\frac{\pi}{4}=45°\\\\B=\frac{\pi}{3}=60°

Use sine rule,

\frac{b}{a}=\frac{\sinB}{\sin A}&#10;\\\\=\frac{\sin{\frac{\pi}{3}}&#10;}{\sin{\frac{\pi}{4}}}\\\\=\frac{[\frac{\sqrt{3}}{2}]}{\frac{1}{\sqrt{2}}}\\\\=\frac{\sqrt{2}}{2}\times \frac{\sqrt{2}}{1}=\sqrt{\frac{3}{2}}

Again consider,

\frac{b}{a}=\frac{\sin{B}}{\sin{A}}&#10;\\\\\sin{B}=\frac{b}{a}\times \sin{A}\\\\\sin{B}=\sqrt{\frac{3}{2}}\sin {A}\\\\B=\sin^{-1}[\sqrt{\frac{3}{2}}\sin{A}]

Thus, the angle B is function of A is, B=\sin^{-1}[\sqrt{\frac{3}{2}}\sin{A}]

Now find \frac{dB}{dA}

Differentiate implicitly the function \sin{B}=\sqrt{\frac{3}{2}}\sin{A} with respect to A to get,

\cos {B}.\frac{dB}{dA}=\sqrt{\frac{3}{2}}\cos A\\\\\frac{dB}{dA}=\sqrt{\frac{3}{2}}.\frac{\cos A}{\cos B}

b)

When A=\frac{\pi}{4},B=\frac{\pi}{3}, the value of \frac{dB}{dA} is,

\frac{dB}{dA}=\sqrt{\frac{3}{2}}.\frac{\cos {\frac{\pi}{4}}}{\cos {\frac{\pi}{3}}}\\\\=\sqrt{\frac{3}{2}}.\frac{\frac{1}{\sqrt{2}}}{\frac{1}{2}}\\\\=\sqrt{3}

c)

In general, the linear approximation at x= a is,

f(x)=f'(x).(x-a)+f(a)

Here the function f(A)=B=\sin^{-1}[\sqrt{\frac{3}{2}}\sin{A}]

At A=\frac{\pi}{4}

f(\frac{\pi}{4})=B=\sin^{-1}[\sqrt{\frac{3}{2}}\sin{\frac{\pi}{4}}]\\\\=\sin^{-1}[\sqrt{\frac{3}{2}}.\frac{1}{\sqrt{2}}]\\\\\=\sin^{-1}(\frac{\sqrt{2}}{2})\\\\=\frac{\pi}{3}

And,

f'(A)=\frac{dB}{dA}=\sqrt{3} from part b

Therefore, the linear approximation at A=\frac{\pi}{4} is,

f(x)=f'(A).(x-A)+f(A)\\\\=f'(\frac{\pi}{4}).(x-\frac{\pi}{4})+f(\frac{\pi}{4})\\\\=\sqrt{3}.[x-\frac{\pi}{4}]+\frac{\pi}{3}

d)

Use part (c), when A=46°, B is approximately,

B=f(46°)=\sqrt{3}[46°-\frac{\pi}{4}]+\frac{\pi}{3}\\\\=\sqrt{3}(1°)+\frac{\pi}{3}\\\\=61.732°

8 0
3 years ago
PLEASE HELP WILL MARK BRAINLIEST THANK YOU
Tanya [424]

Answer:

6? I'm not sure honestly

4 0
2 years ago
Read 2 more answers
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