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Helen [10]
3 years ago
14

0.3 in the form a and b

Mathematics
1 answer:
konstantin123 [22]3 years ago
5 0
The only way I am can you I love my you can be do not know want r a to a party in for you every night before a federal court and then it will
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Can someone answer this question please?
Anna007 [38]

Answer:

For more than 35 miles company A will charge less than company B

Step-by-step explanation:

Let us write the equation of the cost of each company

Company A:

∵ Company A charges $96 for unlimited mileage

∴ The cost of company A = 96

Company B:

∵ Company B charges an initial fee of $75

∵ It charges $0.6 for every mile driven

∵ The number of miles is m

- Multiply m by 0.6 and add 75 to the product

∴ The cost of company B = 75 + 0.6 m

∵ Company A will charge less than company b

∴ 96 < 75 + 0.6 m

- Subtract 75 from both sides

∴ 21 < 0.6 m

- Divide both sides by 0.6

∴ 35 < m

- That means m is greater than 35

∴ m > 35

For more than 35 miles company A will charge less than company B

7 0
3 years ago
Type the correct answer in each box. Use numerals instead of words.
Natali5045456 [20]

Given:

Consider the given function is f(x)=-(x+1)(x-3)(x+2).

To find:

The remaining zero and y-coordinate of y-intercept.

Solution:

We have,

f(x)=-(x+1)(x-3)(x+2)

For zeros, f(x)=0.

-(x+1)(x-3)(x+2)=0

(x+1)(x-3)(x+2)=0

(x+1)=0,(x-3)=0,(x+2)=0

x=-1,x=3,x=-2

So, three zeros of given function are -1, 3 and -2.

Putting x=0 in the given function, we get

f(0)=-(0+1)(0-3)(0+2)

f(0)=-(1)(-3)(2)

f(0)=-(-6)

f(0)=6

So, the y-coordinate of y-intercept of the given function is 6. It means the y-intercept is at point (0,6).

Therefore, the zeros of the function f(x)=-(x+1)(x-3)(x+2) are –1, 3, and -2 and the y-intercept of the function is located at (0,6).

7 0
3 years ago
Which is the graph of a quadratic equation that has a negative discriminant?
vovikov84 [41]

Answer:

Here's what I get  

Step-by-step explanation:

The formula for a quadratic equation is

ax² + bx + c = 0

The quadratic formula gives the roots:

x = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a} =  \dfrac{-b\pm\sqrt{D}}{2a}

D is the discriminant.

It tells us the number of roots to the equation — the number of times the graph crosses the x-axis.

D = \begin{cases}\text{positive}  & \quad \text{2 real solutions}\\\text{zero} & \quad \text{1 real solution}\\\text{negative} & \quad \text{0 real solutions}\\\end{cases}

It doesn't matter if the graph opens upwards or downwards.

If D > 0, the graph crosses the x-axis at two points.

If D = 0, the graph touches the x-axis at one point.

If D < 0, the graph never reaches the x-axis.

Your graph must look like one of the two graphs on the right in the Figure below.

5 0
3 years ago
PLEASE HELP I GIVE THANKS
ololo11 [35]
The answer would be B because it crosses the X axis closer to the 0,0 than the original line
5 0
3 years ago
Can I have some help
Brums [2.3K]

\frac{100}{40}  =  \frac{z + 69}{z}  \\ 100z = 40z  + 2760 \\ 60z = 2760 \\ z = 46
6 0
4 years ago
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