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3 years ago

0.3 in the form a and b

1 answer:

5 0

The only way I am can you I love my you can be do not know want r a to a party in for you every night before a federal court and then it will

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Please answer this correctly without making mistakes

Gekata [30.6K]

Answer:

Step-by-step explanation:

The distance is given by

d = sqrt( (x2-x1) ^2 + ( y2-y1) ^2)

Since the x values are the same

d = sqrt( ( y2-y1) ^2)

d = sqrt( (( -6 - 10)^2))

d = sqrt((-16) ^2)

d = 16

We can also just find the number of squares between the points since the x value is the same.

10 - -6

10+6

4 0

2 years ago

Read 2 more answers

Use an inequality symbol (<,>,=,<_) to compare -3+7____-10-2

Oliga [24]

Answer:

Step-by-step explanation:

-3+7= 4

-10-2= -12

4> -12

6 0

3 years ago

In the figure shown, ABC is a right triangle with side lengths a, b, and c, and CD is an altitude to side AB. The side lengths o

ycow [4]

Answer:

Step-by-step explanation:

In the figure shown, ABC is a right triangle with side lengths a, b, and c, and CD is an altitude to side AB. This altitude divides the triangle into two right triangles ADC and BDC. In these triangles,

$\angle CBD\cong \angle ACD\cong \angle CBA$
$\angle DCB\cong \angle DAC\cong \angle BAC$

So,

$\triangle ABC\sim \triangle CBD\sim \triangle ACD$

1. From the similarity $\triangle ABC\sim \triangle CBD,$ you have

$\dfrac{AB}{BC}=\dfrac{BC}{BD}\\ \\\dfrac{c}{a}=\dfrac{a}{s}$

2. From the similarity $\triangle ABC\sim \triangle ACD,$ you have

$\dfrac{AB}{AC}=\dfrac{AC}{AD}\\ \\\dfrac{c}{b}=\dfrac{b}{r}$

Hence, option A is true

5 0

2 years ago

8. How many ways can a committee of 5 students be chosen from a student council of 30 students? Is the order in which the member

tankabanditka [31]

Answer: A committee of 5 students can be chosen from a student council of 30 students in 142506 ways.

No , the order in which the members of the committee are chosen is not important.

Step-by-step explanation:

Given : The total number of students in the council = 30

The number of students needed to be chosen = 5

The order in which the members of the committee are chosen does not matter.

So we Combinations (If order matters then we use permutations.)

The number of combinations of to select r things of n things = $^nC_r=\dfrac{n!}{r!(n-r)!}$

So the number of ways a committee of 5 students can be chosen from a student council of 30 students= $^{30}C_5=\dfrac{30!}{5!(30-5)!}$

$=\dfrac{30\times29\times28\times27\times26\times25!}{(120)\times25!}=142506$

Therefore , a committee of 5 students can be chosen from a student council of 30 students in 142506 ways.

4 0

2 years ago

Ratna , who is in Mumbai , telephones her brother Ravi in Ahmedabad and speaks for 89 seconds . She is charged Rs 1.20 for every

blondinia [14]

Answer:

16.40

Step-by-step explanation:

3 min-> 180 s

180÷16≈11

11+1=12

12x1.20=14.40

14.40 + 2 = 16.40

7 0

2 years ago