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Anarel [89]
3 years ago
11

Here's the data (sorted) of the ages of 91 women who won the Oscar for Best Actress in a Leading Role:

Mathematics
1 answer:
Harlamova29_29 [7]3 years ago
8 0

the right answer would be A.55

I just to a test with this on it and got it right

hope this helps

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True or false the opposite angles of a quadrilateral in a circumscribed circle are always complementary
ella [17]

Answer: This statement is false.

Step-by-step explanation:

False, the opposite angles of a quadrilateral in a circumscribed circle is not complementary.

As we know that the sum of opposite angles of a cyclic quadrilateral ( quadrilateral circumscribed circle ) is always supplementary.

So, Sum of opposite angles is 180° .

Hence, this statement is false.

7 0
3 years ago
Read 2 more answers
What is the slope of the line that passes thought the points (-7,-7)and(-7,1) write your answer in simplest form.
Alexxandr [17]

Answer:

The slope is undefined

Step-by-step explanation:

Find slope by using the slope formula, m=\frac{y2-y1}{x2-x1}

Use the given points and insert the x's and y's to solve for slope

(-7, -7) (-7, 1)

m=\frac{y2-y1}{x2-x1}

m=\frac{1-(-7)}{-7-(-7)}

m= \frac{8}{0}

m = undefined

The slope for the given point is undefined because it is impossible to divide a number by 0

8 0
3 years ago
Y=<br><img src="https://tex.z-dn.net/?f=y%20%3D%20%20%5Csqrt%7Bx%20-%207%20-%201%7D%20" id="TexFormula1" title="y = \sqrt{x - 7
CaHeK987 [17]
I would say that you cannot answer the question if you dont know either the X-value or Y-value. You need to know at least one of them to figure out the other.
4 0
3 years ago
Read 2 more answers
Can you help me to solve this<br>​
RUDIKE [14]

Answer:

Is the question even complete ?

Step-by-step explanation:

5 0
2 years ago
Verify sine law by taking triangle in 4 quadrant<br>Explain with figure.<br>​
Ksivusya [100]

Proof of the Law of Sines

The Law of Sines states that for any triangle ABC, with sides a,b,c (see below)

a

 sin  A

=

b

 sin  B

=

c

 sin  C

For more see Law of Sines.

Acute triangles

Draw the altitude h from the vertex A of the triangle

From the definition of the sine function

 sin  B =

h

c

    a n d        sin  C =

h

b

or

h = c  sin  B     a n d       h = b  sin  C

Since they are both equal to h

c  sin  B = b  sin  C

Dividing through by sinB and then sinC

c

 sin  C

=

b

 sin  B

Repeat the above, this time with the altitude drawn from point B

Using a similar method it can be shown that in this case

c

 sin  C

=

a

 sin  A

Combining (4) and (5) :

a

 sin  A

=

b

 sin  B

=

c

 sin  C

- Q.E.D

Obtuse Triangles

The proof above requires that we draw two altitudes of the triangle. In the case of obtuse triangles, two of the altitudes are outside the triangle, so we need a slightly different proof. It uses one interior altitude as above, but also one exterior altitude.

First the interior altitude. This is the same as the proof for acute triangles above.

Draw the altitude h from the vertex A of the triangle

 sin  B =

h

c

      a n d          sin  C =

h

b

or

h = c  sin  B       a n d         h = b  sin  C

Since they are both equal to h

c  sin  B = b  sin  C

Dividing through by sinB and then sinC

c

 sin  C

=

b

 sin  B

Draw the second altitude h from B. This requires extending the side b:

The angles BAC and BAK are supplementary, so the sine of both are the same.

(see Supplementary angles trig identities)

Angle A is BAC, so

 sin  A =

h

c

or

h = c  sin  A

In the larger triangle CBK

 sin  C =

h

a

or

h = a  sin  C

From (6) and (7) since they are both equal to h

c  sin  A = a  sin  C

Dividing through by sinA then sinC:

a

 sin  A

=

c

 sin  C

Combining (4) and (9):

a

 sin  A

=

b

 sin  B

=

c

 sin  C

7 0
3 years ago
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