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Maurinko [17]
3 years ago
14

I need help on this I don’t understand how to do this

Mathematics
1 answer:
stepan [7]3 years ago
8 0

Answer:

Hi there!

The correct answer to this question is: The <u>side length</u> of the square base is 18 inches and the <u>height</u> of the pyramid is 9 inches.

Step-by-step explanation:

The equation to find the volume of a square pyramid is V= (b^2)(h/3)

we are given the volume to be 972 inches cubed, additionally we know that the base of the square is x inches, the height is x/2

then we plug in and we get 972= (x^2)(x/2/3)

then you simplify to 972 = x^3 / 6 then you multiply six on both sides and  you get x^3 = 5832

cube root on both sides and you get x = 18 that means the base is 18 inches and the height is x/2 then you plug 18 in and you get the height to be 9 inches.

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Dalia buys 20 collectible gems per month. Grace sells 10 gems from her collection of 120 each month. When will Dalia have more g
4vir4ik [10]

Answer: after 5 months

Step-by-step explanation:

Let x be the number of months it takes for Dalia to have more gems than Grace.

We can set up an inequality; the left side representing Dalia and the right side representing Grace

20x > 120-10x

We can add 10x to both sides:

30x > 120

We can divide both sides by 30:

x > 4

Therefore, after 5 months Dalia will have more gems than Grace.

7 0
2 years ago
What area formula does a triangle have?
ANTONII [103]

Answer:

The area of a triangle can be found using:

a=1/2 bh

or

a=(bh)/2

where b is the base and h is the height

7 0
3 years ago
Read 2 more answers
A metallurgist has one alloy containing 34% copper another containing 48% copper. How many pounds of each alloy must he use to m
Zielflug [23.3K]

Answer:

<h2>36.14 pounds of 34% copper alloy and 9.86 pounds of 48% copper alloy</h2>

Step-by-step explanation:

        First alloy contains 34% copper and the second alloy contains 48% alloy.

We wish to make 46 pounds of a third alloy containing 37% copper.

       Let the weight of first alloy used be x in pounds and the weight of second alloy used be y in pounds.

       Total weight = 46\text{ }pounds=x+y        -(i)

      Total weight of copper = 37\%\text{ of 46 pounds = }34\%\text{ of }x\text{ pounds + }48\%\text{ of }y\text{ pounds }

       \dfrac{37\times 46}{100}=\dfrac{34x}{100}+\dfrac{48y}{100}\\\\ 34x+48y=1702        -(ii)

       Subtracting 34 times first equation from second equation,

34x+48y-34x-34y=1702-34\times46\\14y=138\\y=9.857\text{ }pounds \\x=36.143\text{ }pounds

∴ 36.14 pounds of first alloy and 9.86 pounds of second alloy were used.

5 0
3 years ago
plez help me it comes with 98 points ill even mark your answer as the brainliest plzz i really need the answer
Keith_Richards [23]

Answer:

a = 100

b = 5

Step-by-step explanation:

Just plug this into the equation it shows:

R(1) = (500 + (100)(1)) (50 - (5)(1))

4 0
3 years ago
Read 2 more answers
I need help with a math equation, it’s due by 3:00.
Vilka [71]

Answer:

         2x        -7

2x      4x²      -14x

-1       -2x        +7

Step-by-step explanation:

4x²-16x+7 factors as

(2x-7)(2x-1)

So the grid would be:

         2x        -7

2x      4x²      -14x

-1       -2x        +7

4 0
2 years ago
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