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saveliy_v [14]
3 years ago
7

Both the football and volleyball teams have games today. The football team plays every 7 days. The volleyball team plays every 3

days. When will both teams have games on the same day again?
Mathematics
1 answer:
Allisa [31]3 years ago
6 0
They will have games on the same day in 21 days
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A coin is flipped three times, and the following list shows the possible outcomes.
ahrayia [7]

Answer:

3 outcomes

Step-by-step explanation:

question asks only 1 head therefore THT, TTH, HTT

5 0
2 years ago
Find the limit. Use l'Hospital's Rule if appropriate. If there is a more elementary method, consider using it. lim x→0+ (2x + 1)
ElenaW [278]

\displaystyle\lim_{x\to0^+}(2x+1)\cot x=\lim_{x\to0^+}\frac{2x+1}{\tan x}

As x\to0, the numerator approaches 1 while \tan x\to0, but since x\to0 from above we have \tan x>0, which suggests the limit is +\infty.

3 0
2 years ago
Select the correct answer.<br> Which function has the same graph as x + y = 11?
Zinaida [17]

The function that has the same graph as x + y = 11 is f(x) = -x + 11

<h3>Graph of functions</h3>

From the question, we are to determine the function that has the same graph as the given equation

The given equation is

x + y = 11

In the above equation, y is the dependent variable.

and

Among the given equation, f(x) is the dependent variable

Thus, we can write that

x + f(x) = 11

Isolate f(x)

f(x) = -x + 11

Hence, the function that has the same graph as x + y = 11 is f(x) = -x + 11

Learn more on Graph of functions here: brainly.com/question/20388062

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8 0
2 years ago
368 base 9 plus 788 base 9
anygoal [31]

Answer:

1267

Step-by-step explanation:

and and here is your answer. you're welcome.

so do I get brainliest now

7 0
2 years ago
Evaluate the integral by reversing the order of integration. Integral from 0 to 1 integral from √x to 1 of 5/(y³+1) dydx
ELEN [110]

Answer:

⁵/₃ ln 2

Step-by-step explanation:

∫₀¹ ∫√ₓ¹ 5 / (y³ + 1) dy dx

We want to change the order of integration.  To do this, we start by graphing the region contained by the four limits.

x = 0, x = 1

y = √x, y = 1

(Notice that y = √x is the same as x = y²).

Once we've graphed the region, we need to write the domain of x in terms of y.  In this case, 0 < x < y².

Then, we find the range: 0 < y < 1.

Now we can rewrite the integral:

∫₀¹ ∫₀ʸ² 5 / (y³ + 1) dx dy

Notice that the integrand itself, 5 / (y³ + 1), does not change.  Only the limits have changed.

Solve the integral.

∫₀¹ [ 5 / (y³ + 1) x |₀ʸ² ] dy

∫₀¹ [ 5y² / (y³ + 1) ] dy

⁵/₃ ∫₀¹ [ 3y² / (y³ + 1) ] dy

(⁵/₃ ln|y³ + 1|) |₀¹

⁵/₃ ln|1³ + 1| − ⁵/₃ ln|0³ + 1|

⁵/₃ ln 2

7 0
3 years ago
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